Question

Air friction damps a tuning fork so the amplitude decreases by 1/10 per second. Resonances] 10 Hz. what % chnge in frequency results?

Answer 1

Answer:

The percentage change in frequency is 10%.

Explanation:

Given that,

Amplitude decreases by 1/10 per second.

Resonance = 10 Hz

We need to calculate the change in frequency

Using formula of change in frequency

$\Delta f=\Delta A\times R$

Put the value into the formula

$\Delta f=\dfrac{1}{10}\times10$

$\Delta f=1\ Hz$

We need to calculate the resonant frequency

Using formula of resonant frequency

$f_{r}=R-\Delta f$

Put the value into the formula

$f_{r}=10-1$

$f_{r}=9\ Hz$

We need to calculate the percentage change in frequency

Using formula of percentage change in frequency

$f=\dfrac{10-9}{10}$

$f=10\%$

Hence, The percentage change in frequency is 10%.