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Serjik [45]
3 years ago
8

A block of mass 10.1kg rests on a slope an angle of 43.9∘ relative to the horizontal. What is the size of the force parallel to

the slope, in Newtons?
Use a gravitational acceleration value of g = 9.8m/s^2.
Physics
1 answer:
Julli [10]3 years ago
8 0
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A person wears a hearing aid that uniformly increases the sound level of all audible frequencies of sound by 28.1 dB. The hearin
ladessa [460]

Answer:

 I₂ = 2.13 x 10⁻⁸ W/m²

Explanation:

given,

increase in sound level = 28.1 dB

frequency of the sound = 250 Hz

intensity = 3.3 x 10⁻¹¹ W/m²

Intensity delivered = ?

the difference of intensity level is give as

\beta_2-\beta_1 = 10log(\dfrac{I_2}{I_o}) - 10log(\dfrac{I_1}{I_o})

\beta_2-\beta_1 = 10(log(\dfrac{I_2}{I_o}) -log(\dfrac{I_1}{I_o}))

\beta_2-\beta_1 = 10(log(\dfrac{I_2}{I_1})

28.1= 10(log(\dfrac{I_2}{I_1})

log\dfrac{I_2}{I_1}=2.81

\dfrac{I_2}{I_1}=10^{2.81}

 I₂ = 645.65 I₁

 I₂ = 645.65 x 3.3 x 10⁻¹¹

 I₂ = 2.13 x 10⁻⁸ W/m²

4 0
3 years ago
1) A net force of 75.5 N is applied horizontally to slide a 225 kg crate across the floor.
dimulka [17.4K]

Answer:

The acceleration of the crate is 0.3356\,\frac{m}{s^2}

Explanation:

Recall the formula that relates force,mass and acceleration from newton's second law;

F=m\,a

Then in our case, we know the force applied and we know the mass of the crate, so we can solve for the acceleration as shown below:

F=m\,a\\75.5\,N=225\,\,kg\,\,a\\a=\frac{75.5}{225} \,\frac{m}{s^2} \\a=0.3356\,\,\frac{m}{s^2}

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Answer:

i would say the heavier object

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Answer:

When the polythene rod is rubbed with the woolen cloth, static electric charges move from the cloth and into the rod. The rod becomes negatively charged as negative charges move from the cloth and into the rod leaving the cloth positively charged as well.

5 0
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