Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
![\mu = 502, \sigma = 115](https://tex.z-dn.net/?f=%5Cmu%20%3D%20502%2C%20%5Csigma%20%3D%20115)
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{590 - 502}{115}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B590%20-%20502%7D%7B115%7D)
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{400 - 502}{115}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B400%20-%20502%7D%7B115%7D)
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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She could use the following methods:
8 dimes
16 nickles
2 quarter and 3 dimes
2 quarters and 6 nickles
so, 4 combos
Answer:Please include images of the graphs!
Answer:
The profit made is;
b) $285)
Step-by-step explanation:
The given parameters are;
The number of shares bought, n = 50
The price each share is bought, CP = $55
The amount at which each share is sold, SP = $61
The amount the broker received per share, E = $0.30
Therefore, the amount of profit, 'P', is given as follows;
P = n × (SP - CP - E)
By substituting the values for the variables, we have;
P = 50 × (61 - 55 - 0.3) = 285
The amount made as profit, P = $285.00.
Answer:
2275
Step-by-step explanation:
9100/4 = 2275
this is why you don't go to college, you get boatloads of debt