Answer:
56.2÷6.02×10^23
=9.34×10^23
Explanation:
Divide the given mass of the atom by the mass of an Atom (the avogadro's constant) to find the number of atoms in the given mass.
Explanation:
first you get moles of silver
n=m/M
hence you add no of moles to this equation
c=nv
v=n/c
Answer:
The approximate mass of beryllium is 9.0045 u.
Explanation:
Given data:
mass of helium= 4.002 u
mass of beryllium which is 2.25 times of mass of helium= ?
Solution:
we will multiply the mass of helium with 2.25 times,
4.002 u × 2.25 = 9.0045 u
so the mass of beryllium atom would be 9.0045 u.
The molarity of HBr solution is 0.239 M
calculation
write the equation for reaction
that is LiOH +HBr → LiBr +H20
find the moles of LiOH used
moles =molarity x volume
=0.205 x 29.15 = 5.976 moles
by use of mole ratio between LiOH :HBr which is 1:1 the moles of HBr is therefore= 5.976 moles
Molarity of HCL= moles /volume
= 5.976/25 = 0.239 M
Answer:
The mass of the substance
