The answer is B I had took that last year
There is 3.58 He in the balloon.
Answer:
226.8 mg of mupirocin powder are required
Explanation:
Given that;
weight of standard pack = 22 g
mupirocin by weight = 2%
so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g
so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment
mg of mupirocin powder are required = ?, lets rep this with x
Total weight of ointment = 22 + x g
Amount of mupirocin = 0.44 + x g
percentage of mupirocin in ointment is 3?
so
3/100 = 0.44 + x g / 22 + x g
3( 22 + x g ) = 100( 0.44 + x g )
66 + 3x g = 44 + 100x g
66 - 44 = 100x g - 3x g
97 x g = 22
x g = 22 / 97
x g = 0.2268 g
we know that; 1 gram = 1000 Milligram
so 0.2268 g = x mg
x mg = 0.2268 × 1000
x mg = 226.8 mg
Therefore, 226.8 mg of mupirocin powder are required
Answer:
123.2 Liters.
Explanation:
At STP (T = 273K & P = 1atm)<em>, one mol of any gas will occupy 22.4 liters</em>.
With the above information in mind, we can <u>calculate how many liters would 5.500 mol of gas occupy</u>:
5.500 mol * 22.4 L / mol = 123.2 L
So 5.500 moles of C₃H₃ would have a volume of 123.2 liters at STP.
Answer:
B) There are weak interactions between the CO2 molecules.
Explanation:
Carbon dioxide is composed of one carbon atom that is structured between two atoms of oxygen, they are bonded with double bond and the CO2 is symmetrical because of the arrangement of the bond between them.It is less electronegative than Oxgen, this gives Oxgen the ability to attract the electron to themselves, and there is no intermolecular existing within carbon dioxide other bands waal forces.Compounds that are gases under the condition of room temperatures, and pressure usually have have small molecules. and their molecules is usually have van der Waals forces acting between them and theses forces are weak.This allows carbon dioxide molecules to be able to move freely as a gas.
