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Gre4nikov [31]
3 years ago
5

Why co does not obey lewis octet rule

Chemistry
2 answers:
Nostrana [21]3 years ago
7 0
Carbon monoxide atoms have two different ions Cu + and Cu2 + .such atoms do not obey the octet rule .

thats it :)..
Anuta_ua [19.1K]3 years ago
6 0
Carbon has four electrons and oxygen has six. If only one bond were to be formed between C and O, carbon would have five electrons and oxygen 7.<span>To complete the carbon and oxygen octets in CO, we must employ a triple bond.Even though there is no completion of octet rule.
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What are the science definitions of these
Alecsey [184]

Answer:

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Era

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Explanation:

3 0
3 years ago
Consider a box divided in half. One side is filled with 1 mol Ne at 300. Kelvin, and the other is filled with 1 mol Rn at 300. K
vlada-n [284]

It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.

We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;

t1 = time taken for Rn to equilibrate = 4.0 s

t2 = time taken for Ne to equilibrate = ?

M1 = molar mass of Rn = 222g/mol

M2 = molar mass of Ne = 20 g/mol

Using

t1/t2 = √M1/M2

4/t2 = √222/20

4/t2 = 3.33

t2 = 4/3.33

t2 = 1.2 seconds

Learn more about diffusion in gases: brainly.com/question/879602

3 0
3 years ago
Bob rides his horse 52 km in 3 hours 15 minutes. What is his average speed in kilometers per hour?​
laila [671]
I think the answer is 16.51
7 0
3 years ago
Zinc carbonate dissolves in water to the extent of 1.12 x 10-4 g/L at 25 C. Calculate the solubility product Ksp for ZnCO3 at 25
sashaice [31]

Answer:

Ksp= 7.98 × 10^-13

Explanation:

According to the question, we are to calculate the solubility constant (Ksp) of Zinc carbonate (ZnCO3) in a dissolved solution.

The equilibrium of the reaction is:

ZnCO3 (aq) ⇌ Zn2+ (aq) + CO32- (aq)

According to this; 1 mole of Zinc carbonate (ZnCO3) dissolves to give 1 mole of Zinc ion (Zn2+) and 1 mole of carbonate ion (CO32-).

This illustrates that:

(Zn2+) = 1.12 x 10-4 g/L

(CO32-) = 1.12 x 10-4 g/L

However, 1.12 x 10-4 g/L is the solubility in mass concentration of ZnCO3, we need to convert it to molar concentration in mol/L by dividing by the relative molar mass of ZnCO3.

To calculate the molar mass of ZnCO3, we say:

Zn (65.4) + C (12) + 03 (16×3)

= 65.4+12+48

= 125.4g/mol.

Hence, molar concentration= 1.12 x 10-4 g/L / 125.4 g/mol

= 8.93 × 10^-7 mol/L.

Therefore;

Zn2+) = 8.93 x 10-7 mol/L

(CO32-) = 8.93 x 10-7 mol/L

Ksp = [Zn2+] [CO32-]

Ksp = (8.93 x 10-7) × (8.93 x 10-7)

Ksp = 7.98 × 10^-13

3 0
3 years ago
The hybridization for the B in Bcl3 is ?
Phoenix [80]

Answer:

sp²

Explanation:

You need to look at how many electron orbitals around the atom.  Looking at the structure below, you can see that there are three electron orbitals.  This gives you an sp² hybridization.

6 0
3 years ago
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