Answer:
Eon-an indefinite and very long period of time, often a period exaggerated for humorous or rhetorical effect.
Era
Paleozoic-its end was marked by mass extinctions
mesozoic-between cenozoic and paleozoic
cenozoic- most recent era
period-a length of time
epoch-age
mass extinction- a huge die off of animals
landbridge- a strip of land connecting two large land masses
geographic isolation-island
Explanation:
It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.
We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;
t1 = time taken for Rn to equilibrate = 4.0 s
t2 = time taken for Ne to equilibrate = ?
M1 = molar mass of Rn = 222g/mol
M2 = molar mass of Ne = 20 g/mol
Using
t1/t2 = √M1/M2
4/t2 = √222/20
4/t2 = 3.33
t2 = 4/3.33
t2 = 1.2 seconds
Learn more about diffusion in gases: brainly.com/question/879602
Answer:
Ksp= 7.98 × 10^-13
Explanation:
According to the question, we are to calculate the solubility constant (Ksp) of Zinc carbonate (ZnCO3) in a dissolved solution.
The equilibrium of the reaction is:
ZnCO3 (aq) ⇌ Zn2+ (aq) + CO32- (aq)
According to this; 1 mole of Zinc carbonate (ZnCO3) dissolves to give 1 mole of Zinc ion (Zn2+) and 1 mole of carbonate ion (CO32-).
This illustrates that:
(Zn2+) = 1.12 x 10-4 g/L
(CO32-) = 1.12 x 10-4 g/L
However, 1.12 x 10-4 g/L is the solubility in mass concentration of ZnCO3, we need to convert it to molar concentration in mol/L by dividing by the relative molar mass of ZnCO3.
To calculate the molar mass of ZnCO3, we say:
Zn (65.4) + C (12) + 03 (16×3)
= 65.4+12+48
= 125.4g/mol.
Hence, molar concentration= 1.12 x 10-4 g/L / 125.4 g/mol
= 8.93 × 10^-7 mol/L.
Therefore;
Zn2+) = 8.93 x 10-7 mol/L
(CO32-) = 8.93 x 10-7 mol/L
Ksp = [Zn2+] [CO32-]
Ksp = (8.93 x 10-7) × (8.93 x 10-7)
Ksp = 7.98 × 10^-13
Answer:
sp²
Explanation:
You need to look at how many electron orbitals around the atom. Looking at the structure below, you can see that there are three electron orbitals. This gives you an sp² hybridization.
