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Mrac [35]
3 years ago
11

Bob rides his horse 52 km in 3 hours 15 minutes. What is his average speed in kilometers per hour?​

Chemistry
1 answer:
laila [671]3 years ago
7 0
I think the answer is 16.51
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Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are
sertanlavr [38]

Answer:

Reaction A and B are unfavorable.

Explanation:

Gibbs free energy is an energy which that can be use to convert into useful work.

ΔG°=ΔH°-TΔS°

ΔG°= Gibbs free energy

ΔH° =  enthalpy of reaction

T = temperature of eh reaction

ΔS° = Entropy change

  • If the Gibbs  free energy of the reaction is positive than the reaction will be non spontaneous and the chemical reaction will be not feasible.
  • If the Gibbs  free energy of the reaction is negative than the reaction will be spontaneous and the chemical reaction will be feasible .

According to given information in the question:

Reaction A and B are non spontaneous as their Gibbs free energy value is positive.hence both are unfavorable.

3 0
3 years ago
Two moles of nitrogen are initially at 10 bar and 600 K in piston/cylinder device. The system is expanded adiabatically against
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What net force is required to cause a 12,000 kg airplane to accelerate at a rate of 5.2 m/s
galina1969 [7]
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6 0
2 years ago
What type of minerals are these??
skelet666 [1.2K]

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6 0
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Read 2 more answers
Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm8 at 27 ∘C. (R =
maxonik [38]

Answer:

Total pressure =  56.77 bar

Explanation:

Given data:

Mass of dioxygen = 8 g

Mass of dihydrogen = 4 g

Volume of vessel = 1 dm³

Temperature = 27°C (27+273 = 300 K)

R = 0.083 bar.dm³ / mol.K

Total pressure = ?

Solution:

Number of moles of dioxygen:

Number of moles = mass/molar mass

Number of moles = 8 g/ 32 g/mol

Number of moles = 0.25 mol

Pressure of dioxygen:

PV = nRT

P = nRT/V

P = 0.25 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 6.97 bar.dm³  /1 dm³

P = 6.97 bar

Number of moles of dihydrogen:

Number of moles = mass/molar mass

Number of moles = 4 g/ 2 g/mol

Number of moles = 2 mol

Pressure of dihydrogen:

PV = nRT

P = nRT/V

P = 2 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 49.8 bar.dm³  /1 dm³

P = 49.8 bar

Total pressure of mixture in a vessel:

Total pressure = P (O₂) + P(H₂)

Total pressure =  6.97 bar + 49.8 bar

Total pressure =  56.77 bar

7 0
3 years ago
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