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finlep [7]
3 years ago
13

Which of the following is true about the distribution of water in the hydrosphere?

Chemistry
1 answer:
mr Goodwill [35]3 years ago
5 0
<span>The answer is: C. The amount of water in the hydrosphere remains constant. 

</span>The hydrosphere denotes the entire water available worldwide in lakes and streams, subsurface water, the ice of glaciers, and water vapor in the atmosphere. The water cycle is the process that converts liquid water to atmospheric water vapor (and vice versa) throughout the world.
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Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what
kozerog [31]

Answer: 300 K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles)

V=kT

Given : V= 6.0 L

k= 0.020 L/K

T=?

6.0=0.020LK^{-1}\times T

T=300 K

Thus temperature of the gas is 300 K.

3 0
2 years ago
A student would like to determine how heating a liquid changes its volume. The student hypothesizes that the liquid will increas
worty [1.4K]

Answer:

The volume of the liquid should be measured before it is heated.  

Explanation:

Because During an experiment to test how a variable changes a substance, it is important to first observe and record the characteristics of the substance before the variable is introduced. In this case, the variable is heat energy.  

7 0
2 years ago
An acidic fog in pasadena was found to have a ph of 2.50. which expression represents this ph measurement?
joja [24]

Supposing a temperature of 25 degrees and supposing that all activity coefficients are 1 

pH = -log[H+] 
pOH = -log[OH-] 
pH + pOH = 14 

Thus a pH of 2.50 would mean that the [H+], the concentration of the hydrogen ion, would be 10^(-2.50) 

pH + pOH = 14 
pOH = 14 - pH = 14 - 2.5 = 11.5 
MOH- levels would be coordinated with pOH 
pOH = -log[OH-] ==> [OH-] = [MOH-] = 10^-pOH = 10^-11.5 = 3.2 x 10^-12 

Therefore, MOH¯ = 3.2 × 10¯12 M 

5 0
3 years ago
What is the ∆G for the following reaction between O3 and O2? 3O2(g) 2O3(g) Given: O3: ∆H = 285.4 kJ ∆S = -137.14 J/K)
Natali [406]
We’ll be using the equation:
dG = dH - TdS (replace ‘d’ with triangle)

I’m going to assume 0 degrees Celsius.
At 0 C (273 K):

dG = dH - TdS
dG = (285,400 J) - (273 K)(-137.14 J/K)
dG = 285,400 J + 37,439.2 J
dG = 322,839.2 J or 322.84 kJ

The dG of this reaction is +322.84 kJ. This reaction is not considered spontaneous.

This answer, in this instance, would be D. If the temperature used in the question is not 0 degrees C, replace the temperature that I used for calculation with the Kelvin temperature given in the problem (K = C + 273), and simplify to find the answer.
6 0
3 years ago
What is the correct name for the formula, Mno
Ksivusya [100]

Answer: Manganese(II) oxide

Explanation:

7 0
3 years ago
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