Answer:
Speed greater than 4 m/s
Explanation:
Given that Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs to run to the tree, 12 meters away. If it takes her cat, 3 seconds to fall, how fast would Ms. Kasper have to run to save her cat?
The distance = 12 m
Time = 3s
Speed = distance/time
Speed = 12/3
Speed = 4 m/s
Ms Kasper must run at speed more than 4m/s for her to save the cat.
X Represents the distance the spring is stretched or compressed away from its equilibrium or rest position.
Answer: Tension = 47.8N, Δx = 11.5×
m.
Tension = 95.6N, Δx = 15.4×
m
Explanation: A speed of wave on a string under a tension force can be calculated as:

is tension force (N)
μ is linear density (kg/m)
Determining velocity:


0.0935 m/s
The displacement a pulse traveled in 1.23ms:


Δx = 11.5×
With tension of 47.8N, a pulse will travel Δx = 11.5×
m.
Doubling Tension:



|v| = 0.1252 m/s
Displacement for same time:


15.4×
With doubled tension, it travels
15.4×
m
I think the answer to this problem I believe would probably be B. learned optimism. I think it's the closest answer...I THINK
Answer:
Option d is correct.
The magnitude of the resultant force upon the piling = 2930 lbs.
Explanation:
Resultant of a group of forces = vector sum of the forces.
Force 1 = (-1250î) lbs
Force 2 = (2650j) lbs
Resultant = (-1250î + 2650j) lbs
The magnitude of the resultant = √[(-1250)² + (2650)²] = 2930 lbs.
Or in visualization method, the two forces presented form a right angled triangle with the resultant of the two forces.
Hence, using Pythagoras theorem,
F₁² + F₂² = R²
(1250)² + (2650)² = R²
R = √[(1250)² + (2650)²] = 2930 lbs.