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3 years ago

14

Does anyone know this???

1 answer:

Gelneren [198K]3 years ago

8 0

Answer:

C

Explanation:

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Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs t

Misha Larkins [42]

Answer:

Speed greater than 4 m/s

Explanation:

Given that Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs to run to the tree, 12 meters away. If it takes her cat, 3 seconds to fall, how fast would Ms. Kasper have to run to save her cat?

The distance = 12 m

Time = 3s

Speed = distance/time

Speed = 12/3

Speed = 4 m/s

Ms Kasper must run at speed more than 4m/s for her to save the cat.

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2 years ago

In Hooke’s law, what does the x represent?

Arte-miy333 [17]

X Represents the distance the spring is stretched or compressed away from its equilibrium or rest position.

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3 years ago

Read 2 more answers

10. How far does a transverse pulse travel in 1.23 ms on a string with a density of 5.47 × 10−3 kg/m under tension of 47.8 ?????

KATRIN_1 [288]

Answer: Tension = 47.8N, Δx = 11.5× $10^{-6}$ m.

Tension = 95.6N, Δx = 15.4× $10^{-5}$ m

Explanation: A speed of wave on a string under a tension force can be calculated as:

$|v| = \sqrt{\frac{F_{T}}{\mu} }$

$F_{T}$ is tension force (N)

μ is linear density (kg/m)

Determining velocity:

$|v| = \sqrt{\frac{47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{0.00874 }$

$|v| =$ 0.0935 m/s

The displacement a pulse traveled in 1.23ms:

$\Delta x = |v|.t$

$\Delta x = 9.35.10^{-2}*1.23.10^{-3}$

Δx = 11.5× $10^{-6}$

With tension of 47.8N, a pulse will travel Δx = 11.5× $10^{-6}$ m.

Doubling Tension:

$|v| = \sqrt{\frac{2*47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{2.0.00874 }$

$|v| = \sqrt{0.01568}$

|v| = 0.1252 m/s

Displacement for same time:

$\Delta x = |v|.t$

$\Delta x = 12.52.10^{-2}*1.23.10^{-3}$

$\Delta x =$ 15.4× $10^{-5}$

With doubled tension, it travels $\Delta x =$ 15.4× $10^{-5}$ m

4 0

3 years ago

On Ella's fifth birthday, her parents told her she had to stop whining or no one would want to play with her. She tried very har

Kisachek [45]

I think the answer to this problem I believe would probably be B. learned optimism. I think it's the closest answer...I THINK

3 0

2 years ago

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A piling for a high-rise building is pushed by two bulldozers at exactly the same time. One bulldozer exerts a force of 1250 pou

Ierofanga [76]

Answer:

Option d is correct.

The magnitude of the resultant force upon the piling = 2930 lbs.

Explanation:

Resultant of a group of forces = vector sum of the forces.

Force 1 = (-1250î) lbs

Force 2 = (2650j) lbs

Resultant = (-1250î + 2650j) lbs

The magnitude of the resultant = √[(-1250)² + (2650)²] = 2930 lbs.

Or in visualization method, the two forces presented form a right angled triangle with the resultant of the two forces.

Hence, using Pythagoras theorem,

F₁² + F₂² = R²

(1250)² + (2650)² = R²

R = √[(1250)² + (2650)²] = 2930 lbs.

7 0

3 years ago