Does anyone know this???

A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt

GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

Weight of sculpture - Weight of water displaced = 13.86 N

15.76 - Weight of water displaced = 13.86

Weight of water displaced = 1.9 N

Mass of water displaced = 0.194 kg

Mass = Volume x Density

0.194 = V x 1000

Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity = Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0

3 years ago

Which causes a rainbow in the sky?

Vilka [71]

I might be wrong but I'm pretty sure It's B

7 0

2 years ago

A cryogenic vacuum pump works by condensing vapors onto some absorbent medium. This is an efficient and clean way to pump a syst

Julli [10]

Answer: Temperature in Fahrenheit is 577.4

Explanation:

The conversion factor for converting celcius to Fahrenheit is:

$F=\frac{9}{5}\times C+32$

where F = temperature in Fahrenheit

C = Temperature in Celcius

Given : Temperature difference in Celcius = $303^0C$

Putting in the values we get:

$F=\frac{9}{5}\times 303+32$

$F=577.4$

Thus the answer in Fahrenheit is 577.4

6 0

2 years ago

A sack of groceries with a mas of 22 kg is lifted off the floor with a velocity of 6 m/s. What is the kinetic energy of the sack

AnnyKZ [126]

the answer is 396 joules :D

5 0

3 years ago

A solid sphere is released from the top of a ramp that is at a height h1 = 2.30 m. It rolls down the ramp without slipping. The

Oksi-84 [34.3K]

Answer:

The horizontal distance d does the ball travel before landing is 1.72 m.

Explanation:

Given that,

Height of ramp $h_{1}=2.30\ m$

Height of bottom of ramp $h_{2}=1.69\ m$

Diameter = 0.17 m

Suppose we need to calculate the horizontal distance d does the ball travel before landing?

We need to calculate the time

Using equation of motion

$h_{2}=ut+\dfrac{1}{2}gt^2$

$t=\sqrt{\dfrac{2h_{2}}{g}}$

$t=\sqrt{\dfrac{2\times1.69}{9.8}}$

$t=0.587\ sec$

We need to calculate the velocity of the ball

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2$

$K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times(\dfrac{2}{5}mr^2)\times(\dfrac{v}{r})^2$

$K.E=\dfrac{7}{10}mv^2$

Using conservation of energy

$K.E=mg(h_{1}-h_{2})$

$\dfrac{7}{10}mv^2=mg(h_{1}-h_{2})$

$v^2=\dfrac{10}{7}\times g(h_{1}-h_{2})$

Put the value into the formula

$v=\sqrt{\dfrac{10\times9.8\times(2.30-1.69)}{7}}$

$v=2.922\ m/s$

We need to calculate the horizontal distance d does the ball travel before landing

Using formula of distance

$d =vt$

Where. d = distance

t = time

v = velocity

Put the value into the formula

$d=2.922\times 0.587$

$d=1.72\ m$

Hence, The horizontal distance d does the ball travel before landing is 1.72 m.

8 0

3 years ago