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UkoKoshka [18]
3 years ago
10

A given atom has 3 protons, 4 neutrons, and 3 electrons. Describe how you can use those three values to describe the structure,

charge, and mass of the atom.
Physics
2 answers:
pogonyaev3 years ago
5 0
<span>The atomic number of a neutral atom is equal to the number of protons and the number of electrons of the atom. The atomic weight meanwhile is equal to the sum of the number of protons and number of neutrons. In this case, the atomic number of the atom is 3 and the atomic mass is 7. Hence the element is Lithium, a metal </span>
lilavasa [31]3 years ago
3 0

Answer and Explanation;

Structure; the nucleus has 3 protons and 4 neutrons, while the energy levels or the orbitals have 3 electrons. The identity atom is lithium atom (3 protons and three electrons) with an electron configuration of 1s^2 2s.

Charge; the atom has zero charge; it is neutral because the number of protons is equal to the number of electrons.

Its atomic number is 3; since atomic number is the number of protons in the nucleus of an atom (3 protons).

It has a mass number of 7; mass number is the sum of neutrons and protons in the nucleus of an atom ( 3 protons + 4 neutrons).

Atoms contain three sub-atomic particles called protons, neutrons and electrons. The protons and neutrons are found in the nucleus at the center of the atom. The nucleus is very much smaller than the atom as a whole. The electrons are arranged in shells around the nucleus.

In a neutral atom the number of electrons in an atom is always the same as the number of protons (protons = electrons).

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What is the Force in Newtons exerted by an object with a mass of 15 kg and an Acceleration of 12 m/s2?
ZanzabumX [31]
Force = mass * acceleration
F = ma
F = (15)(12)
F = 180N
5 0
3 years ago
2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from
Natalija [7]

Answer:

105 m/s

Explanation:

Given that the speed of train A, V_A = 45 m/s from west to east.

Speed of train B, V_B = 60 m/s from east to west.

Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.

So, the speed of train A from east to west= - 45 m/s

The speed of train B w.r.t train A = V_B - V_A=60-(-45)=60+45=105 m/s

Hence, the speed of train B w.r.t train A is 105 m/s from east to west.

5 0
3 years ago
A car is traveling at a speed of 54 km/h. Breaks are applied so as to produce a uniform acceleration of -0.5 m/s2. Find how far
Lena [83]

Explanation:

u=54 km/h

54*5/18=15 m/s

v=0m/s

t=?

acceleration=-0.5m/s^2

we know that a=v-u/t

so,

t=v-u/a

t=15-0/0.5

=15/0.5

=30

therefore, the time is 30 second

Hope this answer helps you..

8 0
3 years ago
A runner exerts a net force of 335 n to accelerate at a rate of 2.5 m/s what is the runners mass
Olegator [25]
F=ma
M=F/a
M=335/2.5
M=134 kg
8 0
3 years ago
Why is it important to know the direction of the force applied to a moving object and the direction in which the object is movin
erastova [34]

Answer

(C).

When there is an angle between the two directions, the cosine of the angle must be considered.


Step by step Solution

The work done by a force is defined as the product of the force and the distance traveled in the direction of motion.

The first answer "Only the component of the force perpendicular to the motion is used to calculate the work" is wrong because, the force perpendicular to motion does no work.

The second choice "If the force acts in the same direction as the motion, then no work is done" is wrong because the work in the direction of the force is W=F\times d.

Fourth answer "A force at a right angle to the motion requires the use of the sine of the angle" is wrong because the sin(90)=0 meaning that there is no work done in the direction perpendicular to the motion.

The third answer" When there is an angle between the two directions, the cosine of the angle must be considered." is correct because the work is calculated using the force in the direction of the motion. The magnitude of this force is F\times d\times \cos(\theta).




4 0
3 years ago
Read 2 more answers
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