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3 years ago

2 Physics Questions WILL GIVE BRAINLIEST!!

Physics

1 answer:

In-s [12.5K]3 years ago

5 0

Answer:

a) The force of friction is 1.5 N.

b) The new force is 4/9 times as large as the original force.

Explanation:

It is given that the book is moving on the table.

∴ The friction acting on the block should be kinetic.

∴ Coeffecient of kinetic friction , k = 0.3

The force of friction = kN , where 'N' is the normal force acting on the surface where friction is acting.

In this case , N = mg , where 'm' is the mass of the book and 'g' is the acceleration due to gravity.

∴ Force of friction , f = kmg = 0.3×0.5×10 = 1.5N

b) We know that ,

Gravitational force , F ∝ m , where 'm' is the mass of the body.

F ∝ $x^{2}$ where 'x' is the distance between the two bodies.

Since mass of both the bodies is doubled , the force will be 4 times as large compared to the original force F from the first proportionality equation.

However , as the distance is 3 times as large , the force will be 9 times as small as compared to the original force F

∴ The new force is 4/9 times as large as the old force

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(b) During one day, 250 kg of water is pumped through

ser-zykov [4K]

Answer: The energy incident on the solar panel during that day is $9.24 \times 10^{7} J$ .

Explanation:

Given: Mass = 250 kg

Initial temperature = $16^{o}C$

Final temperature = $38^{o}C$

Specific heat capacity = 4200 $J/kg^{o}C$

Formula used to calculate the energy is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass of substance

C = specific heat capacity

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C$

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

$\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J$

Thus, we can conclude that the energy incident on the solar panel during that day is $9.24 \times 10^{7} J$ .

4 0

2 years ago

A point charge of -2 µC is located at the origin. A second point charge of 6 µC is at x = 1 m, y = 0.5 m. Find the x and y coord

Soloha48 [4]

Answer:

x coordinate = -1.66 m

y coordinate is = -0.825m

Explanation:

Suppose z be the distance form the first charge and z + sqrt(1^2 +.5^2) be the distance from the second So z + sqrt(1+.25) = z + 1.12

We have k*2.0x10^-6/s^2 = k*6x10^-6/(s+1.12)^2

0.0356s^2 -0.019s-0.0897=0

s=1.876m

The angle of the line between the two charges is arctan(.5/1) = 26.6o

x coordinate = -1.876*cos(26.6) = -1.66m

y coordinate is -1.876*sin(26.6) = -0.825m

3 0

3 years ago

Which of the following is proportional to the net external force acting on a body?

swat32

Well, Velocity is the speed of something in a given direction, and speed is the rate at which someone or something is able to more or operate. They both invlove speed, so this is a hard one, but I wold say either B or D

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2 years ago

In what type of job might being a difficult person not be much of a liability ?

zhannawk [14.2K]

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3 years ago

What is the energy per photon absorbed during the transition from n = 2 to n = 3 in the hydrogen atom?

adelina 88 [10]

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