The final velocity of the ice is 82.0 m/s
Explanation:
The chuck of ice in this problem is in free fall, so we can use the following suvat equation for uniformly accelerated motion:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
In this problem, we have:
u = 0 is the initial velocity of the chuck of ice
is the acceleration of gravity (we choose downward as positive direction)
s = 343 m is the vertical displacement (the height of the tower)
Solving for v, we find the final velocity of the object:
Learn more about free fall motion here:
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