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babunello [35]
3 years ago
6

(a) calculate the molarity of a solution made by dissolving 0.0815 mol na2so4 in enough water to form exactly 550. ml of solutio

n.
Chemistry
1 answer:
Vesna [10]3 years ago
4 0
You just need to convert it into moles per Liter (mol/L).

0.0815mol / 0.550L = 0.148mol/L
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The density of mercury is 13.5g/mL. What is the volume of this liquid if the sample weighs 12.5 pounds?
Mama L [17]

Answer : The volume of liquid is 420 mL.

Explanation :

Density : The mass per unit volume of a substance is known as density.

Formula used:

\text{Density}=\frac{\text{Mass}}{\text{Volume}}

As we are given:

Density of mercury = 13.5 g/mL

Mass = 12.5 pounds

First we have to convert mass of sample from pound to gram.

Conversion used:

As, 1 pound = 453.6 g

So, 12.5 pounds = 453.6 × 12.5 g = 5670 g

Now we have to calculate the volume of liquid.

\text{Density}=\frac{\text{Mass}}{\text{Volume}}

Now putting all the given values in this formula, we get:

13.5g/mL=\frac{5670g}{\text{Volume}}

Volume = 420 mL

Therefore, the volume of liquid is 420 mL.

7 0
4 years ago
Which particle has a mass of approximately 1 atomic mass unit?
labwork [276]
The answer is D) a neutron.

When we say an atom's mass is, like 5 atomic mass units actually we are saying that the total number of the neutrons and protons in its nucleus is 5.

The mass of a neutron and a proton is each one atomic mass unit.

Mass of a neutron is approximately 1 atomic mass unit.
7 0
3 years ago
Convert 0.00200 g into Mg and answer in scientific notation:
Masja [62]

Answer: 2.00x10^{2}

Explanation: 1 gram is equal to 1000 Milligrams so

0.00200g=\frac{1000mg}{1g}

Since you go straight across its just multiplication so 0.00200x1000=200mg

To answer it in scientific notation it should just be 2.00x10^{2} mg

5 0
2 years ago
If the vapor pressure of ethanol at 34.7degree C is 100
saw5 [17]

Answer:

we will use the Clausius-Clapeyron equation to estimate the vapour pressures of the boiling ethanol at sea level pressure of 760mmHg:

 ln (P2/P1) = \frac{ΔvapH}{R}([tex]\frac{1}{T1}-\frac{1}{T2})

where

P1 and P2 are the vapour pressures at temperatures  T1 and T2

Δ vapH  = the enthalpy of vaporization of the ETHANOL

R  = the Universal Gas Constant

In this problem,

P 1 = 100 mmHg

;  T 1 = 34.7 °C = 307.07 K

P 2 = 760mmHg

T 2 =T⁻²=?

Δ vap H = 38.6 kJ/mol

R = 0.008314 kJ⋅K -1 mol -1

ln ( 760/10)=(0.00325 - T⁻²) (38.6kJ⋅mol-1 /0.008314 )

0.0004368=(0.00325 - T⁻²)  

T⁻²=0.002813

T² = 355.47K

6 0
3 years ago
The single bond is
Alex17521 [72]
4 is correct for this one
3 0
3 years ago
Read 2 more answers
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