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Lapatulllka [165]
3 years ago
7

What is the primary difference between and hypothesis and a theory

Chemistry
1 answer:
zysi [14]3 years ago
6 0
A hypothesis is an assumption made before an experiment while a theory is made after collecting a lot of scientific evidence.
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GIVE BRAINLIST AND HURRY IM IN TEST
Yanka [14]

Answer:

c - Record !!

7 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!!
alekssr [168]

Answer: Temperature and number of moles are the conditions which remain constant in Boyle's law.

Explanation:

Boyle's law states that at constant temperature the pressure of a gas is inversely proportional to the volume of gas.

Mathematically, it is represented as follows.

P \propto \frac{1}{V}

As equation for ideal gas is as follows.

PV = nRT

And, at constant temperature the pressure is inversely proportional to volume which also means that number of moles are also constant in Boyle's law.

Thus, we can conclude that temperature and number of moles are the conditions which remain constant in Boyle's law.

5 0
3 years ago
How many liters of 4 M solution can be made using 100 grams of lithium bromide?
andriy [413]
Molar mass of LiBr ( lithium bromide ) =  <span>86.845 g/mol

</span><span>Amount of calculation to moles of lithium bromide (LiBr)

86.845 g ------------- 1 mole
100 g ----------------- ?

n = m / M

n = 100 / 86.845

n = 1.1514 moles of LiBr

 V  ---------------------1.1514 moles
1 L  --------------------  4 M

1.1514 * 1 / 4

V = 1151.4 / 4

V = 0,28785 L

hope this helps!

hope this helps !</span>
8 0
3 years ago
Give the balanced chemical reaction for the preparation of black oxide from blue vitriol​
sasho [114]

Answer:

Blue vitriol is crystal copper sulphate

Explanation:

The black oxide is the higher oxide of Copper i.e Cu. It is also called as tenorite. It is solid black in color. It is formed by heating copper with air.

$2Cu +O_2 \rightarrow 2CuO$

Blue vitriol is the crystalline form of copper sulphate. It is also known as copper (II) sulphate.

When heating, the blue vitriol undergoes various steps of changes to the black oxide of copper.

The chemical reaction is --

$CuSO_4 \cdot5H_2O \rightarrow CuSO_4\cdot 3H_2O {\rightarrow} CuSO_4\cdot H_2O \rightarrow CuSO_3 \rightarrow CuO +SO_2+O_2

3 0
3 years ago
Calculate the pH of a solution that is 2.00 M HF, 1.00 M NaOH, and 0.472 M NaF. (Ka=7,2×104)
eduard

Explanation:

The given data is as follows.

Concentration of acid, [HF] = 2 M

Concentration of salt, [NaF] = 0.472 M

Concentration of base, [NaOH] = 1.00 M

K_{a} = 7.2 \times 10^{-4}

So, NaOH being a base will react with the acid that is, HF. And, according to Henderson-Hasselbalch equation we have he following.

             pH = pK_{a} + log\frac{[salt]}{[acid]}

Also, we known that pK_{a} = -log K_{a}

so,                     pK_{a} = -log 7.2 \times 10^{-4}

                         pK_{a} = 3.1426

Hence,    pH = 3.1426 + log\frac{0.472 M}{2 M}

               pH = 2.5155

Thus, we can conclude that pH of the solution is 2.5155.

8 0
3 years ago
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