The position of the particle is given by:
x(t) = t³ - 12t² + 21t - 9
Differentiate x(t) with respect to t to find the velocity x'(t):
x'(t) = 3t² - 24t + 21
Differentiate x'(t) with respect to t to find the acceleration x''(t):
x''(t) = 6t - 24
Acceleration is mathematically defined as; ΔV/t.
<h3>What is acceleration?</h3>
Acceleration is defined as the ratio of the change in velocity to time. It is defined as the extent to which the velocity changes within a given time interval.
The question is incomplete so we can not arrive at the final answer. However, acceleration is mathematically defined as; ΔV/t.
Learn more about acceleration: brainly.com/question/2437624
Answer: 6s
Explanation:
Vs=32m/s speed at beginning of slowing down
Vf=0m/s stop speed
a= -6 m/s² acceleration
----------------
Use equation for acceleration :
a=(Vf-Vs)/t
a*t=Vf-Vs
t=(Vf-Vs)/a
t=(0-36)/-6
t=-36/-6
t=6 s
I think it should be option (b)
Pressure = Force/ Area = 3000/2 = 1500 pascal.