I don't know what you mean by the question, but in science it is Newton's second law.
"The second law explains how the velocity of an object changes when it is subjected to an external force."
I hope this helped!+*♡
Answer:
Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is 45.249 kiloJoules.
Explanation:
Mass of the tin ,m= 425 g
Heat capacity of the tin ,c= 0.227 J/g K
Initial temperature of the tin ,
= 25.0 °C = 298.15 K
Final temperature of the tin,
= 231.9 °C = 505.05 K
Let the heat required to change the temperature of tin from 298.15 K to 505.05 K be Q.


Heat required to melt tin at 505.05 K be Q'
The heat of fusion of tin metal =

Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is:
= Q+Q' = 19.961 kJ + 25.288 kJ = 45.249 kJ
There are 8 atoms in 2Ca(CIO2)2
1694520 joules
i honestly looked it up on google
Answer:
Boron Carbonate; B₂(CO₃)₃
Explanation:
For names, carbonide does not exist; that rules out the first option. Carbide refers to just a carbon atom, not carbon and oxygen as in the polyatomic ion carbonate. That rids us of the third option. We are left with boron carbonate with the formula BCO or boron carbonate with the formula B₂(CO₃)₃.
Recall the carbonate polyatomic ion's formula: CO₃²⁻
Thus BCO cannot be the formula.
Option 4 is your answer, Boron Carbonate; B₂(CO₃)₃.
To further check your answer, observe the oxidation states of boron and the polyatomic ion carbonate. Boron can exist in oxidation states of either 2+ or 3+, and carbonate is only 2-; in this formula, boron will exhibit a 3+ state to balance out with carbonate.
2x3+ = 6+; 3x2- = 6-
6+ + 6- = 0; balanced