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Oksanka [162]
3 years ago
14

54,000,000 nanometers equals 0.000000054 megameters.

Chemistry
2 answers:
masha68 [24]3 years ago
6 0

Answer:

They are equals.

Explanation:

Hello!

Let's solve this!

In order to know if this is correct, we will have to convert to meters and see if it gives the same result.

Since nanometer is 1 * 10 ^ -9, then

54,000,000 nanometers = 0.054 meters

Megameter is 1 * 10 ^ + 6, so

0.000000054 megameters = 0.054 meters.

With these calculations, we verify that they are the same.

LiRa [457]3 years ago
3 0
That is true b<span>ecause 1 nanometer = 1.0 × 10^-15 megameters.</span>
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2. When 400 J of heat is added to 5.6 g of olive oil at 23*C, the temperature increases to 87*C. What is the specific heat of th
Maksim231197 [3]

Answer:

The answer to your question is C = 1.116 J/g°C

Explanation:

Data

Q = 400 J

mass = 5.6 g

Temperature 1 = T1 = 23°C

Temperature 2 = T2 = 87°C

Specific heat = C = ?

Formula

Q = mC(T2 - T1)

- Solve for C

C = Q / m(T2 - T1)

- Substitution

C = 400 / 5.6 (87 - 23)

- Simplification

C = 400 / 5.6(64)

C = 400 / 358.4

- Result

C = 1.116 J/g°C

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4 years ago
According to the following reaction, how many grams of water are produced in the complete reaction of 29.7 grams of ammonia? 4 N
Gnesinka [82]

<u>Answer:</u> The mass of water produced in the reaction is 47.25 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of ammonia = 29.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{29.7g}{17g/mol}=1.75mol

The given chemical reaction follows:

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By stoichiometry of the reaction:

4 moles of ammonia produces 6 moles of water.

So, 1.75 moles of ammonia will produce = \frac{6}{4}\times 1.75=2.625mol of water.

Now, calculating the mass of water by using equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 2.625 moles

Putting values in equation 1, we get:

2.625mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=47.25g

Hence, the mass of water produced in the reaction is 47.25 grams.

3 0
3 years ago
2. If you are given the mass of a reactant in grams and want to calculate the mass of
Darina [25.2K]

Answer:

1. Convert given mass of reactant to moles.

2. Convert moles of reactant to moles of product using the coefficients in the balanced equation.

3. Convert moles of product back to grams of product

Explanation:

In order to find out the mass of a given product in grams you would have to convert the grams into moles by multiplying 1 mole over the given mass of the reactant. Then, you would convert the moles of the reactant into moles of the product using mole ratio. And lastly, you would multiply by the mass of the product to calculate the mass back to grams.

Hope this helps!!<3

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