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OlgaM077 [116]
3 years ago
13

Which element(s) is/are not balanced in this equation? Pb(NO3)2 +2 Kcl -> pbCl2 + KNO3

Chemistry
2 answers:
UkoKoshka [18]3 years ago
4 0

Answer:

The correct answer is KNO3

Explanation:

Pb(NO3)2 +2 KCl -> PbCl2 + KNO3

If we look at the left side of the equation we could see that there are 1 lead atom, 2 nitrate atoms ,2 potassium atoms and 2 chlorine atoms

Now when we look at the right side of the equation, we found that there are –  

1 lead atom and  2 chlorine atoms (PbCl2)  , thus lead and chlorine are balanced as they have the same number of atom in LHS and RHS

There is only 1 potassium and 1 nitrate atom on RHS , thus KNO3 is not balanced.  

The balanced equation would be –  

Pb(NO3)2 +2 KCl -> PbCl2 +2 KNO3

Murljashka [212]3 years ago
4 0

Answer : The elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

Pb(NO_3)_2+2KCl\rightarrow PbCl_2+KNO_3

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of nitrogen, potassium and oxygen are not balanced while all the atoms are balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the 'KNO_3'.

Thus, the balanced chemical reaction will be,

Pb(NO_3)_2+2KCl\rightarrow PbCl_2+2KNO_3

Hence, elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

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You are requested to reduce the size of 50 ton/hr of a given solid. The size of the feed is such 80% passes a 4-in (76.2 mm) scr
defon

Answer:

1) The power needed to process 50 ton/hr is 135.4 HP.

2) The void fraction of the bed is 0.37.

Explanation:

1) For this type of milling operations, we can estimate the power needed for an operation according to the work index (Ei), the passing size of the circuit feed (F80) and the passing size of the product (P80).

We assume the units of Ei are kWh/t.

The equation that relates this parameters and the power is (size of particles in μm):

W=Ei*(\frac{10}{\sqrt{P80}} -\frac{10}{\sqrt{F80}} )\\\\W=9.45*(\frac{10}{\sqrt{3175\mu m}} -\frac{10}{\sqrt{76200mm}} )\\\\\\W=9.45*(0.1774+0.0362)=2.019 kWh/t

The power needed to process 50 ton/hor is

P=2.0194\frac{kWh}{Ton}*\frac{50Ton}{h}*\frac{1.341HP}{1kW}=   135.4 \, HP

2) The density of the packed bed can be expressed as

\rho=f_v*\rho_v+f_s*\rho_s

being f the fraction and ρ the density of every fraction. We know that the density of the void is 0 (ρv=0) and that fv=1-fs (the sum  of the fractions ois equal to the total space).

Then we can rearrange

\rho=f_v*\rho_v+f_s*\rho_s\\\\\rho=f_v*0+(1-f_v)*\rho_s\\\\\rho/\rho_s=1-f_v\\\\f_v=1-\rho/\rho_s=1-990/1570=1-0.63=0.37

The void fraction of the bed is 0.37.

6 0
3 years ago
Which of the following is/are true regarding initial and maximal velocity of enzyme-mediated reactions?
kenny6666 [7]

Answer:

a. True

b. True

c. False

d. True

Explanation:

a). A a very low substrate concentration , $S. Thus according to the Machaelis-Menten equation becomes

$V_0 = \frac{V_{max} \times [S]}{Km}$

Here since the $V_0$ varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option  (a) is true.

b). The Michaelis -Menten kinetics equation states that :

   $V_0 = \frac{V_{max} \times [S]}{Km+[S]}$

  Here the initial velocity changes directly with the substrate concentration as $V_0$ is directly proportional to [S]. But $V_{max}$ is same for any particular concentration of the enzymes. Thus, option (b) is true.

c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.

d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.

7 0
3 years ago
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kondaur [170]

Answer:

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5 0
3 years ago
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saw5 [17]

Answer:

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Explanation:

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-Aircraft cabins are therefore pressurized to maintained a similar pressure as that experienced at sea level to ensure normal breathing of passengers.

6 0
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noname [10]
Number 1 is C number 2 is B and number 3 is also B
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