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OlgaM077 [116]
3 years ago
13

Which element(s) is/are not balanced in this equation? Pb(NO3)2 +2 Kcl -> pbCl2 + KNO3

Chemistry
2 answers:
UkoKoshka [18]3 years ago
4 0

Answer:

The correct answer is KNO3

Explanation:

Pb(NO3)2 +2 KCl -> PbCl2 + KNO3

If we look at the left side of the equation we could see that there are 1 lead atom, 2 nitrate atoms ,2 potassium atoms and 2 chlorine atoms

Now when we look at the right side of the equation, we found that there are –  

1 lead atom and  2 chlorine atoms (PbCl2)  , thus lead and chlorine are balanced as they have the same number of atom in LHS and RHS

There is only 1 potassium and 1 nitrate atom on RHS , thus KNO3 is not balanced.  

The balanced equation would be –  

Pb(NO3)2 +2 KCl -> PbCl2 +2 KNO3

Murljashka [212]3 years ago
4 0

Answer : The elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

Pb(NO_3)_2+2KCl\rightarrow PbCl_2+KNO_3

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of nitrogen, potassium and oxygen are not balanced while all the atoms are balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the 'KNO_3'.

Thus, the balanced chemical reaction will be,

Pb(NO_3)_2+2KCl\rightarrow PbCl_2+2KNO_3

Hence, elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

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Copper has a density of 8.96 g/cm3. If 75.0 g of copper is added to 50.0 mL of water in a graduated cylinder, to what volume rea
Tcecarenko [31]

Answer:

The answer to your question is    Final volume = 58.37 ml

Explanation:

Data

density = 8.96 g/cm³

mass = 75 g

volume of water = 50 ml

Process

1.- Calculate the volume of copper

  Density = mass / volume

Solve for volume

  Volume = mass / density

Substitution

  Volume = 75/8.96

Simplification

  Volume = 8.37cm³    or 8.37 cm³

2.- Calculate the new volume of water in the graduated cylinder

  Final volume = 50 + 8.37

  Final volume = 58.37 ml

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Alpha, Beta, and Gamma Decay

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slader Consider the following reactions: A. uranium-238 emits an alpha particle; B. plutonium-239 emits an alpha parti- cle; C.
pishuonlain [190]

<u>Answer:</u>

<u>For A:</u> The equation is _{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> The equation is _{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> The equation is _{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

<u>Explanation:</u>

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

<u>For A:</u> Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> Thorium-239 emits a beta particle

The nuclear equation for this process follows:

_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

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