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OlgaM077 [116]
3 years ago
13

Which element(s) is/are not balanced in this equation? Pb(NO3)2 +2 Kcl -> pbCl2 + KNO3

Chemistry
2 answers:
UkoKoshka [18]3 years ago
4 0

Answer:

The correct answer is KNO3

Explanation:

Pb(NO3)2 +2 KCl -> PbCl2 + KNO3

If we look at the left side of the equation we could see that there are 1 lead atom, 2 nitrate atoms ,2 potassium atoms and 2 chlorine atoms

Now when we look at the right side of the equation, we found that there are –  

1 lead atom and  2 chlorine atoms (PbCl2)  , thus lead and chlorine are balanced as they have the same number of atom in LHS and RHS

There is only 1 potassium and 1 nitrate atom on RHS , thus KNO3 is not balanced.  

The balanced equation would be –  

Pb(NO3)2 +2 KCl -> PbCl2 +2 KNO3

Murljashka [212]3 years ago
4 0

Answer : The elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

Pb(NO_3)_2+2KCl\rightarrow PbCl_2+KNO_3

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of nitrogen, potassium and oxygen are not balanced while all the atoms are balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the 'KNO_3'.

Thus, the balanced chemical reaction will be,

Pb(NO_3)_2+2KCl\rightarrow PbCl_2+2KNO_3

Hence, elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

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Answer:

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Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 13.90 = 3.791 mg

For hydrogen, H:

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Mass of H = 2/18 x 6.048 = 0.672 mg

For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

Mass of N = 0.561 mg

Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

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N = 0.561 mg

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C = 3.791 / 12 = 0.316

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N = 0.561 / 14 = 0.040

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C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

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