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Vladimir79 [104]
3 years ago
15

50,80,60,50, and 90 find the mean and median of the contribution

Mathematics
1 answer:
fomenos3 years ago
8 0
The median of the question is 60.
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The world famous gambler from Philadelphia, Senor Rick, proposes the following game of chance. You roll a fair die. If you roll
Orlov [11]

Answer:

You lose $0.833 while Rick gains $0.833, and so Rick is not Loco

Step-by-step explanation:

There are six numbers on a dice. Thus, probability of rolling exactly one number = 1/6

Probability of rolling two is 2/6.

Rolling a 1 pays $25, and probability = 1/6

Rolling a 2 pays $5,and probability = 1/6

Rolling a 3 pays $0, and probability = 1/6

Rolling a 4 or 5 pays -$10, and probability = 2/6

Rolling a 6 pays -$15, and probability = 1/6

Thus,lets calculate the expected value;

EV = (25 × 1/6) + (5 × 1/6) + (0 × 1/6) + (-10 × 2/6) + (-15 × 1/6)

EV = - $0.833

This means you lose $0.833 while Rick gains $0.833, and so Rick is not Loco.

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3 years ago
Solve for x in the inequality.
oee [108]

Answer:

C. x < 5

Step-by-step explanation:

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5 0
3 years ago
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Solve for k<br> k - 2/ 5 = 11j
Vikki [24]
You have to move the -2/5 by the 11j to get k by its self
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Preform the indicated operation and express the answer in simplest radical form
tigry1 [53]

hello

the question here is

3\sqrt[]{7}(14-4\sqrt[]{56})

step 1

multiply through the bracket by the coeffiecient

\begin{gathered} 3\sqrt[]{7}(14-4\sqrt[]{56}) \\ (3\sqrt[]{7}\times14)-(3\sqrt[]{7}\times4\sqrt[]{56}) \\ (14\times3\sqrt[]{7})-3\sqrt[]{7}\times4\sqrt[]{4\times14} \\ (42\sqrt[]{7})-3\sqrt[]{7}\times8\sqrt[]{14} \\ (42\sqrt[]{7})-\lbrack(3\times8)\sqrt[]{7\times14} \\ 42\sqrt[]{7}-24\sqrt[]{98} \end{gathered}\begin{gathered} 42\sqrt[]{7}-24\sqrt[]{49\times2} \\ 42\sqrt[]{7}-24\times7\sqrt[]{2} \\ 42\sqrt[]{7}-168\sqrt[]{2} \end{gathered}

5 0
1 year ago
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