We can use the heat
equation,
<span>Q = mcΔT
</span>
Where Q is the amount
of energy transferred (J), m is the mass of the substance (kg), c is the
specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
In this problem there is no any data about initial temperature of the water. So, we can assume that given temperature of 5.2 °C as the temperature difference.
Q = 348 J
m = ?
c = 4.186 J g⁻¹ °C⁻¹
ΔT = 5.2 °C<span>
By applying the formula,
348 J = m x </span>4.186 J g⁻¹ °C⁻¹ x 5.2 °C<span>
m = 15.99 g
Hence, the grams of water is 15.99.</span>
Answer:
Order of the cycle:
Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.
Explanation:
<u>Step -1:</u>
Carbon dioxide is taken in by plants during photosynthesis.
<u>Step -4;</u>
The animal eats a plant and uses its carbohydrates for energy.
<u>Step - 3</u>
The animal releases the carbon dioxide back into the atmosphere during respiration.
<u>Step -2</u>
The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.
Therefore, order of the cycle is Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.
Answer:
sickness.
Explanation:
some bacterium cause sickness, kike a stomach bug.
The empirical formula : C₁₁O₁₄O₃
<h3>Further explanation</h3>
The assumption of the compound consists of C, H, and O
mass of C in CO₂ =
mass of H in H₂O =
mass of O :
mass sample-(mass C + mass H)
mol of C :
mol of H :
mol of O :
divide by 0.0155(the lowest ratio)
C : H : O ⇒
Answer:
27.7 grams of Li
0.140 moles of Co
0.158 moles of K
59.9 grams of As
8.00x10⁻⁹ moles of U
142.8 moles of H
0.0199 moles of O
0.666 moles of Pb
Explanation:
Mass / Molar mass = Mol
Mol . Molar mass = Mass
3.99 m . 6.94 g/m = 27.7 grams of Li
8.28 g / 58.93 g/m = 0.140 moles of Co
6.17 g / 39.1 g/m = 0.158 moles of K
0.8 mol . 74.92 g/m = 59.9 grams of As
6.02x10²³ (NA) particles are contained in 1 mol
6.02x10²³ are contained in 1 mol U____ 1 mol H ____ 1 mol O ___ 1 mol Pb
4.82x10¹⁵ atoms U ____ 4.82x10¹⁵/ 6.02x10²³ = 8.00x10⁻⁹ moles of U
8.60x10²⁵atoms H ____ 8.60x10²⁵ / 6.02x10²³ = 142.8 moles of H
1.20x10²² atoms O ____ 1.20x10²² / 6.02x10²³ = 0.0199 moles of O
4.01x10²³ atoms Pb ____ 4.01x10²³ / 6.02x10²³ = 0.666 moles of Pb
