Answer:
2.3125g
Explanation:
Half-life referred to the time required for a quantity to reduce to half of its initial value, It used to calculate how unstable atoms undergo, or the period of time and atom can survive, radioactive decay.
Given:
t(1/2)= 9.25days
Initial mass of Thulium-167 = 48grams
We need to calculate the remaining amount after 37days.
Since we know that 1 half life = 9.25 days
Then 37 days means ( 37/9.25) half lives
37days means 4 half life
That means the 38grams of Thulium-167 will be halved by 4 times.
Then the ratio between the initial Amount and the amount remaining after 37 days can be calculated as. 0.5^(4)
= 37days × 0.5^(4)
= 2.3125g
the remaining amount of Thallium-167 after 37days is 2.3125g
1 mole = 6.022 * 10^23 formula units.
1.84*10^24 formula units CaCl₂ * (1 mole CaCl₂/6.022*10^23 formula units CaCl₂) = 3.06 moles of CaCl₂.
There are 3.06 moles of CaCl₂.
Answer:
The answer is 1.29473 x 10^24
Explanation:
Explanation:
Noble gases are group O elements and their atomic structure ensures that they are stable. All their orbitals are completely filled with electrons therefore they do not undergo reactions with other elements.
- Heavier noble gases are able to form a range of compounds due their sizes.
- Elements form compounds by exchanging or sharing of their outermost shell electrons called the valence electron.
- Every atom has specific energy required to remove electrons from them. The energy is known as the ionization energy.
- In bigger atoms which have large radius, the outermost electrons have low ionization energy which makes them easy to remove.
- The ionization energy depends on the nuclear charge, the more the charge the higher the ionization energy. Down a group the nuclear charge and ionization decreases.
- As we go down the inert group, the ionization energy of outer shell electrons become very low. This makes the electrons available to take part in chemical reactions.
Learn more:
Noble gas brainly.com/question/10874792
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Elements are used to create bonds and are classified as particles.
