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Ainat [17]
3 years ago
6

8 less than one third of x and y

Mathematics
1 answer:
tester [92]3 years ago
8 0
<span>y=(x/3)−8
hope this helps pls mark me as brainliest</span>
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Figure CDEF is a parallelogram.
NikAS [45]

Answer:

n=10, CF=59, FE=49

6 0
2 years ago
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Select the two values of x that are roots of this equation. 2x2 + 7x + 6 = 0
Anna007 [38]

Answer:

x = -3/2, -2

Step-by-step explanation:

2x^2 + 7x + 6 = 0

(2x + 3)(x + 2) = 0

(2x + 3)

2x = -3

x = -3/2

(x + 2)

x = -2

7 0
2 years ago
Read 2 more answers
Please help it would be much appreciated!!
AlekseyPX

Answer:

a) P) 0.25 = 1/4  both

b) P) 0.75 = 3/4  one

c) P) 0.25  = 1/4  none

Step-by-step explanation:

4 routes to D + H

6 routes to H + S

= D  H   S

     4  | 6

    - 2 | -3

=    2  |  3  = route 1 = 2/4  and route 2 = 3/6

= 1/2 route 1 and 1/2 route 2

Answer a ) = 1/2 x 1/2 = 0.25 = 1/4  = 0.25 probability

Answer b)  = 1- (1/2 x 1/2) = 1- 0.25 = 3/4 = 0.75 probability

Answer c)  = 1/2 x 1/2 = 0.25 = 1/4 = 0.25 probability  

3 0
2 years ago
Circle C with center at (−4, 6) and radius 2 is similar to circle D with center at (6, −2) and radius 4. Below is an incorrect i
BlackZzzverrR [31]

We are told that circle C has center (-4, 6) and a radius of 2.

We are told that circle D has center (6, -2) and a radius of 4.


If we move circle C's center ten units to the right and eight units down, the new center would be at (-4 + 10), (6 - 8) = (6, -2). So step 1 in the informal proof checks out - the centers are the same (which is the definition of concentric) and the shifts are right.

Let's look at our circles. Circle C has a radius of 2 and is inside circle D, whose radius is 4. Between Circle C and Circle D, the radii have a 1:2 ratio, as seen below:

\frac{1}{2} = \frac{radius--circle C}{radius--circle D}

If we dilate circle C by a factor of 2, it means we are expanding it and doubling it. Our circle has that 1:2 ratio, and doubling both sides gives us 2:4. The second step checks out.

Translated objects (or those that you shift) can be congruent, and dilated objects are used with similarity (where you stretch and squeeze). The third step checks out.


Thus, the argument is correct and the last choice is best.

3 0
3 years ago
A certain natural number is not divisible by 7. Can it be divisible by 14, explain why or why not
Elanso [62]
For a number to be divisible by 14 it needs to be both divisible by 7 and 2 which are factors of 14. Every time you have a number (x) to check if it is divisible by some larger number you find the factor of that larger number and check is the x divisible by both.

Answer: it cannot be divisible by 14.
3 0
3 years ago
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