<u>Answer:</u> The volume of HCl needed is 177.2 mL
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of sodium hydrogen carbonate = 23.2 g
Molar mass of sodium hydrogen carbonate = 84 g/mol
Putting values in above equation, we get:

The chemical equation for the reaction of hydrochloric acid and sodium hydrogen carbonate follows:

By Stoichiometry of the reaction:
1 mole of sodium hydrogen carbonate reacts with 1 mole of hydrochloric acid
So, 0.28 moles of sodium hydrogen carbonate will react with =
of hydrochloric acid
To calculate the volume for given molarity, we use the equation:

Molarity of hydrochloric acid = 1.58 M
Moles of hydrochloric acid = 0.28 mol
Putting values in above equation, we get:

Hence, the volume of HCl needed is 177.2 mL