Answer:
2.57 g of H₂
Solution:
The Balance Chemical Equation is as follow,
N₂ + 3 H₂ → 2 NH₃
According to Balance equation,
34.06 g (2 moles) NH₃ is produced by = 6.04 g (3 moles) of H₂
So,
14.51 g of NH₃ will be produced by = X g of H₂
Solving for X,
X = (14.51 g × 6.04 g) ÷ 34.06 g
X = 2.57 g of H₂
Answer:
Yes, water can stay liquid below zero degrees Celsius. There are a few ways in which this can happen. The freezing point of water drops below zero degrees Celsius as you apply pressure. When we apply pressure to a liquid, we force the molecules to get closer together.
Explanation:
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Answer:
A) 7.9 x 10⁶ inches
B) 1004 g
C) 2.8 x 10³ inches/ min
D) 1.2 x 10⁻⁴ mm
Explanation:
A) Since 39.37 inches = 1 m, you can convert meters to inches by multiplying by the conversion factor (39.37 inches / 1 m).
Notice that if 39.37 inches = 1 m then 39.37 inches / 1 m = 1. That means that when you multiply by a conversion factor, you are only changing units since it is the same as multiplying by 1 :
2.0 x 10⁵ m * (39.37 inches / 1 m) = 7.9 x 10⁶ inches
B) Conversion factors : (2.205 pounds / 1 kg) and (453.59 g / 1 pound), because 2.205 pounds = 1 kg and 1 pound = 453.59 g. Then:
1.004 kg * ( 2.205 pounds / 1 kg) * ( 453.59 g / 1 pound) = 1004 g
C) Conversion factor: (39.37 inches / 1 m) and (60 s / 1 min)
1.2 m/s * (39.37 inches / 1 m) * ( 60 s / 1 min) = 2.8 x 10³ inches/ min
D)Converison factor ( 1 mm / 1 x 10⁶ nm):
120 nm (1 mm / 1 x 10⁶ nm) = 1.2 x 10⁻⁴ mm
Answer:
7% 4)2(10
Explanation:
beacouse if you divide it you can get the answer
Answer:
0.0025 M/min
Explanation:
The rate of a reaction can be calculated for an element, based on its stoichiometric coefficient. For a reaction:
aA + bB = cC + dD , the rate will be
r = -(1/a)x(Δ[A]/Δt) = -(1/b)x(Δ[B]/Δt) = (1/c)x(Δ[C]/Δt) = (1/d)x(Δ[D]/Δt)
Where Δ[X] is the variation of the concentration of the X compound, Δt is the time variation, and the signal of minus in the reagents compounds is because they are disappearing, so Δ[X] will be negative, and r must be positive. So, for the reaction given:
r = -(1/2)x(Δ[NO]/Δt)
r = -(1/2)x( (0.025 - 0.1)/15)
r = 0.0025 M/min