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Eva8 [605]
3 years ago
5

How many grams of CaSO4 (Molar mass = 136 g) can be produced if 15.4 g Ca3(PO4)2 (molar mass = 310 g) completely reacts?

Chemistry
1 answer:
kykrilka [37]3 years ago
8 0
Balance Chemical equation is as follow,

                    Ca₃(PO₄)₂  + 3 H₂SO₄   →   3 CaSO₄  +  2 H₃PO₄

According to eq.

     310 g (1 mole) of Ca₃(PO₄)₂ produces  =  408.42 g (3 mole) of CaSO₄
So,
              15.4 g of Ca₃(PO₄)₂ will produce  =  X g of CaSO₄

Solving for X,
                                           X  =  (15.4 g × 408.42 g) ÷ 310 g

                                           X  =  20.28 g of CaSO₄
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3 years ago
If 3.00 mL of 0.0250 M CuSO4 is diluted to 25.0 mL with pure water, what is the molarity of copper(II) sulfate in the diluted so
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0.00268 M

Explanation:

To find the new molarity, you need to (1) find the moles of CuSO₄ (via the molarity equation using the beginning molarity and volume) and then (2) find the new molarity (using the moles and combined volume). Your final answer should have 3 sig figs to match the given values.

<u>Step 1:</u>

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