Question

How many grams of CaSO4 (Molar mass = 136 g) can be produced if 15.4 g Ca3(PO4)2 (molar mass = 310 g) completely reacts?

Answer 1

Balance Chemical equation is as follow,

                    Ca₃(PO₄)₂  + 3 H₂SO₄   →   3 CaSO₄  +  2 H₃PO₄

According to eq.

     310 g (1 mole) of Ca₃(PO₄)₂ produces  =  408.42 g (3 mole) of CaSO₄
So,
              15.4 g of Ca₃(PO₄)₂ will produce  =  X g of CaSO₄

Solving for X,
                                           X  =  (15.4 g × 408.42 g) ÷ 310 g

                                           X  =  20.28 g of CaSO₄