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Zanzabum
3 years ago
15

Student perfotms a Benedict's test on an unknown substance. He adds reagent(the chemical required to make a color change), and n

othing happens. What can you conclude?
Chemistry
1 answer:
elixir [45]3 years ago
7 0

Answer:

Reducing sugars are absent

Explanation:

Benedict's solution is an substance used in testing sugars. It is mixture of sodium carbonate, sodium citrate and copper(II) sulfate pentahydrate. It can be used instead of Fehling's solution in testing for the presence of reducing sugars.

Reducing sugars contain the -CHO group. If there is no colour change after the addition of Benedict's solution, then we can conclude that reducing sugars are absent.

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A weak base is added to water. Which information is required to find the strength of its conjugate acid?
lozanna [386]

Answer: C) the values of Kb and Kw

Explanation: i just took the test

5 0
3 years ago
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How many moles of water are produced when 3.0 moles of hydrogen gas react with 1.8 moles of oxygen gas?
swat32

Sorry for the late response but for this question, the answer is 3 moles of water.

8 0
4 years ago
Is apple juice a homogeneous mixture or a heterogeneous mixture
Solnce55 [7]

If you mean the industrialized apple juice then yes. Even though there are several different compounds and some of them aren't actually dissolved in the liquid, since you can't actually distinguish between them using only your eyes and they do no separate naturally it is actually a homogeneous mixture.


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3 years ago
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2.
Arturiano [62]

Answer:

they are producers and they have means to keep themselves warm

Explanation:

I took test and saw answer.

6 0
3 years ago
A sample of argon gas has a volume of 73 mL at a pressure of 1.20 atm and a temperature of 112 degrees Celsius. What is the fina
NeX [460]

Answer:

V₂ → 106.6 mL

Explanation:

We apply the Ideal Gases Law to solve the problem. For the two situations:

P . V = n . R . T

Moles are still the same so → P. V / R. T = n

As R is a constant, the formula to solve this is: P . V / T

P₁ . V₁ / T₁ = P₂ .V₂ / T₂   Let's replace data:

(1.20 atm . 73mL) / 112°C = (0.55 atm . V₂) / 75°C

((87.6 mL.atm) / 112°C) . 75°C = 0.55 atm . V₂

58.66 mL.atm = 0.55 atm . V₂

58.66 mL.atm / 0.55 atm = V₂ → 106.6 mL

3 0
3 years ago
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