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Gnom [1K]
2 years ago
8

What is the molarity of a solution of KNO3 (molecular mass = 101) that contains 404 grams of KNO3 in 2.00 liters of solution? A.

1.00 B. 2.00 C. 0.500 D. 4.00
Chemistry
1 answer:
ss7ja [257]2 years ago
3 0

Answer:2.00

Explanation:

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What ions will form when baking soda is dissolved in water?
ad-work [718]

Answer:When you add baking powder to water or milk, the alkali and the acidreact with one another and produce carbon dioxide – the bubbles. Sodium bicarbonate is a weak base which is commonly known as baking soda and used in cooking. It weakly ionizes in water: NaHCO3 + H2O → H2CO3 + (OH-) + (Na+). u need to stop deleteing my answers ughh

Explanation:

4 0
3 years ago
If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa
Genrish500 [490]

If the length of a string increases 2 times but the mass of the string remains constant, the original density  will be multiplied by a factor  mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the  volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

v2/v1 = \sqrt{L2/L1}

v2/v1 = \sqrt{2}

In conclusion,v ratio will give us

v=1.414 times

Read more about volume

brainly.com/question/1578538

8 0
2 years ago
Newton's second law of motion is F = ma.
ZanzabumX [31]

<u>Answer:</u> The acceleration of the object is 2m/s^2. If net force increases, acceleration will also increase and if mass increases, the acceleration will decrease.

<u>Explanation:</u>

Force is defined as the product of object's mass and acceleration.

Mathematically,

F = ma     ......(1)

or,

a = F/m      .....(2)

where,

F = Force exerted on an object = 60N

m = mass of an object = 30kg

a = acceleration of the object = ?

Putting values in above equation, we get:

a = 60 kg.m/s^2/30 kg = 2m/s^2

The acceleration of the car is 2m/s^2.

From equation 2, it is visible that acceleration is directly proportional to force. This means that \if force increases, acceleration also increases.

And acceleration is inversely proportional to mass of the object. This means that if mass increases, the acceleration decreases.

Hence, if net force increases, acceleration will also increase and if mass increases, the acceleration will decrease.

7 0
3 years ago
Read 2 more answers
Using the van der waals equation, the pressure in a 22.4 L vessel containing 1.50 mol of chlorine gas at 0.00 c is____________at
MatroZZZ [7]

Answer:

D. 1.48atm

Explanation:

Van der waals equation is given as:

(P +an²/v²) (v - nb) = nRT

Where;

P = pressure (atm)

V = volume (L)

R = gas constant (0.0821 Latm/molK)

a and b = gas constant specific to each gas

T = temperature (K)

n = number of moles

According to the given information; V = 22.4L, T = 0.00°C (273.15K), R = 0.0821 Latm/molK, a = 6.49L^2-atm/mol^2, b = 0.0562 L/mol, n = 1.5mol

Hence;

(P + 6.49 × 1.5²/22.4²) (22.4 - 1.5×0.0562) = 1.5 × 0.0821 × 273.15

(P + 6.49 × 2.25/501.76) (22.4 - 0.0843) = 33.638

(P + 0.0291) (22.316) = 33.638

22.316P + 0.649 = 33.638

22.316P = 33.638 - 0.649

22.316P = 32.989

P = 32.989/22.316

P = 1.478

P = 1.48atm

6 0
3 years ago
A sample of gaseous neon atoms at atmospheric pressure and 0 °c contains 2.69 * 1022 atoms per liter. the atomic radius of neon
omeli [17]

Explanation

Radius of neon atom : 69 pm = 69\times 10^{-12} m

Volume occupied by the one atom:\frac{4}{3}\pi r^3

=\frac{4}{3}\times 3.14\times(69\times 10^{-12} m)^3=1.37\times 10^{-30} m^3

given that 2.69\times 10^{22} atoms are present in 1L

1 L = 0.001 m^3

The volume occupied by the 2.69\times 10^{22} neon atoms

2.69\times 10^{22}\times 1.37\times 10^{-30} m^3=3.68\times 10^{-8} m^3

Fraction of volume occupied by the neon atom:

=\frac{3.68\times 10^{-8} m^3}{0.001 m^3}=3.68\times 10^{-11} m^3

3.68\times 10^{-11} m^3

The fraction of of volume occupied by the neon atom is very less than the 1 L which indicates the presence of large amount of empty space between the atoms of the gas.

3 0
3 years ago
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