Complete Question
The histogram from this question is shown on the first uploaded image
Answer:
The first quartile is 
The median is 
The third quartile is
The mean is 
Step-by-step explanation:
From the question we are told that
The total number of girls is n = 74
Generally the median is mathematically represented as
![Median = \frac{\frac{n}{2} +[ \frac{n}{2} + 1] }{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%5Cfrac%7Bn%7D%7B2%7D%20%20%2B%5B%20%5Cfrac%7Bn%7D%7B2%7D%20%2B%201%5D%20%20%7D%7B2%7D)
So
![Median = \frac{\frac{74}{2} +[ \frac{74}{2} + 1] }{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%5Cfrac%7B74%7D%7B2%7D%20%20%2B%5B%20%5Cfrac%7B74%7D%7B2%7D%20%2B%201%5D%20%20%7D%7B2%7D)
=> 
=>
From the histogram
fall under 2 fruits per day
Generally the first quartile is mathematically represented as
![1st \ Q = \frac{\frac{n}{4} + [\frac{n}{4} + 1] }{2}](https://tex.z-dn.net/?f=1st%20%5C%20Q%20%3D%20%20%5Cfrac%7B%5Cfrac%7Bn%7D%7B4%7D%20%2B%20%5B%5Cfrac%7Bn%7D%7B4%7D%20%2B%201%5D%20%20%7D%7B2%7D)
=> ![1st \ Q = \frac{\frac{74}{4} + [\frac{74}{4} + 1] }{2}](https://tex.z-dn.net/?f=1st%20%5C%20Q%20%3D%20%20%5Cfrac%7B%5Cfrac%7B74%7D%7B4%7D%20%2B%20%5B%5Cfrac%7B74%7D%7B4%7D%20%2B%201%5D%20%20%7D%7B2%7D)
=> 
From the histogram
girl fall under 1 fruit per day
Generally the third quartile is mathematically represented as

=> 
=> 
From the histogram
fall under 4 fruits per day
Generally from the histogram table the frequency [number of subjects (girls) ] and the servings of fruit per day can be represented as
Total
x(servings per day ) 0 1 2 3 4 5 6 7 8
f (number of subjects ) 15 11 15 11 8 5 3 3 3 
xf 0 11 30 33 32 25 18 21 24 
Generally the mean is mathematically represented as
![\= x = \frac{1}{ \sum f} * [\sum xf]](https://tex.z-dn.net/?f=%5C%3D%20x%20%3D%20%5Cfrac%7B1%7D%7B%20%5Csum%20f%7D%20%20%2A%20%5B%5Csum%20xf%5D)
=>
=> 
Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere

The differential of V with respect to r is:

dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
<span>for that, what you need is a calculator... like say a TI(texas instruments) 83 or 83plus or higher, will do regressions, if you have an android device like a phone or tablet, you can also get an app from the play store "Andie's graph", is a TI calculator emulator, it works just like the calculator itself, you'd only need the ROM
</span><span>that said, you can also use some online calculators for that.
</span>
<span>I could give you a direct link to one, but this site has issues with links, if you do a quick search in google for "keisan exponential regression calculator", it should be the first link, is from the Casio site.
</span>
<span>you could do regressions in a spreadsheet as well.... you could check online for an "addin" or "extension", if you use MS Excel, pretty sure there are some addins for regressions.
</span>
if I recall correctly, Excel does regressions natively, but the addins are just frontends, is all, just some added interfacing.
anyhow, if you have an Android device Andie Graph works peachy, I have an 83plus, 84, 86 in it, they all work just like my old TI83plus.
there's also an app in the play store called Graph89, is an emulator for a TI89, the same you need a tiny little file, and texas instruments provides them, have also, works peachy too.
Answer:
answer would be E. 16,000,000
Step-by-step explanation:
if you put 8,180 x 2,099 in the calculator you get 17,169,820
just round that number and you get 16,000,000
hope this helped!!
Answer:
13.9 in
Step-by-step explanation:
Use the Pythagorean Theorem to answer this. Folding the paper along its diagonal produces two triangles; each one has shorter side 8.5 in and longer side 11 in. According to the Pyth. Thm., (8.5)^2 + 11^2 = 193.25, which results in the diagonal length √193.25, or approx. 13.9 in.