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Ira Lisetskai [31]
3 years ago
12

your skin is the largest organ of your body. The skin and its appendages, hair and nails, are known as the integumentary system.

All but one of these are functions of your skin. A) aids in the production of vitamin d b) helps regulate your body temperature c) first line of protection against invaders d) semipermeable membrane to substances like glucose
Chemistry
2 answers:
hichkok12 [17]3 years ago
4 0

Answer: D

Explanation:  

Your skin is not a semipermeable membrane to substances like glucose. Your cell membrane is the semipermeable structure that allows substance, such as glucose and water, to enter your cells.

Eddi Din [679]3 years ago
3 0

Answer:

The correct answer is d

Explanation:

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I need some help with a long chemistry problem. Anything is appreciated!
Mkey [24]

Answer:

The CSI is wrong.  

Explanation:

1. Find the volume of the pool

The formula for the volume of a cylinder is  V = πr²h .

D = 12 m; h = 10 m

r = D/2 = (12 m/2) = 6.0 m

V = πr²h = π × (6.0 m)² × 10 m = π × 36 m²× 10 m = 360π m³ = 1100 m³

= 1.1. × 10⁶ L

2. Calculate the moles of OH⁻

n = cV = 1.0 × 10⁻² mol·L⁻¹ × 1.3 × 10⁶ L = 11 000 mol of OH⁻                                                                                                                                                                                                                                                                                                                              

3. Calculate the moles of acetic acid needed for neutralization

HA + OH⁻ ⟶ A⁻ + H₂O

The molar ratio of is 1 mol HA:1 mol OH⁻, so you need 11 000 moL of acetic acid.

4. Calculate the actual moles of acetic acid

You have four 5 L jugs of acetic acid pH 2 .

Volume = 20 L

[H⁺] = 10⁻² mol·L⁻¹ = 0.01 mol·L⁻¹

(a) Set up an ICE table

                      HA + H₂O ⇌ A⁻  + H₃O⁺

I/mol·L⁻¹:          c                   0         0

I/mol·L⁻¹:     - 0.01             +0.01    +0.01

I/mol·L⁻¹:    c - 0.01             0.01     0.01

K_{\text{a}} = \dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}  = 1.76 \times 10^{-5}

(b) Calculate the concentration of acetic acid

\begin{array}{rcl}\dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}& = & 1.76 \times 10^{-5}\\\\\dfrac{0.01\times 0.01}{c}& = & 1.76 \times 10^{-5}\\\\1 \times 10^{-4} & = & 1.76 \times 10^{-5}c\\c & = & \dfrac{1 \times 10^{-4}}{1.76 \times 10^{-5}}\\\\ & = & \text{6 mol/L}\\\end{array}

The concentration of the acetic acid is 6 mol·L⁻¹

(c) Calculate the moles of acetic acid

n = \text{20 L} \times \dfrac{\text{6 mol}}{\text{1 L}} = \textbf{100 mol}

You have 100 mol of acetic acid.

The CSI is wrong.

You don't have enough acetic acid to neutralize the pool.

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Read 2 more answers
If the solubility of a gas in water is 5.0 g/L when the pressure of the gas above the water is 2.5 atm, what is the pressure of
OLga [1]

Answer:

0.5 atm.

Explanation:

  • Henry’s law states that the amount of a gas dissolved in a  solution is directly proportional to the  pressure of the gas above the solution
  • We should use Henry’s law: <em>P = KC,</em>

where, P is the partial pressure of the  gaseous solute above the solution.

k is a constant.

C is the concentration of the  dissolved gas.

<em>At two different pressures:</em>

<em>P₁C₂ = P₂C₁,</em>

P₁ = 2.5 atm, C₁ = 5.0 g/L.

P₂ = ??? atm, C₂ = 1.0 g/L.

<em>∴ P₂ = P₁C₂/C₁</em> = (2.5 atm)(1.0 g/L)/(5.0 g/L) = <em>0.5 atm.</em>

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Allen is carrying out reactions in a lab. One of the products in all reactions is found to be either a precipitate, a gas, or wa
krek1111 [17]
I think the best answer among the choices given is option A. The reactions are all decomposition reactions because decomposition reactions can produce either a precipitate, a gas and a water in a single reaction. However, these products can also be produced by other type of reactions.
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