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3 years ago

Carpet and tile flooring are at the same room temperature,

Chemistry

1 answer:

monitta3 years ago

8 0

Answer:

Depends on conduction and the texture

Explanation:

it feels softer because tile is expose to the coldness in your building and carpet feels warmer because the texture of it

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What is the volume of 0.4 mole of gas at stp? 30 points!

iragen [17]

Answer:

89.6 liters

Explanation:

A STP (standard temperature and pressure) ONE mole of any idea gas will occupies 22.4 liters. So,...

4 moles x 22.4 L/mol = 89.6 liters

5 0

2 years ago

Read 2 more answers

What would be the major product if 1,4-dibromo-4-methylpentane was allowed to react with:

Levart [38]

Answer : The correct answer for a) 4-bromo-2-iodo-4-methyl pentane and b)5-bromo-2-ethoxy-2-methyl pentane.

A) Reaction with NaI :

Reaction of alkyl halide with NaI is known as Finkelstein Reaction . The acetone is used as solvent . It involves bimolecular nucleophillic substitution rmechanism (SN²) . There is replecement of one halogen with other occurs .

The incoming Nucleophile(Nu⁻) (halide) attacks on carbon from back side , while the leaving group (halide) leaves the compound from front side , simultaneously. The product so formed have is inverted .(Image)

NaI releases I⁻ ion which act as nucelophile and attacks on C1 carbon and Br⁻ from C1 carbon is released . Out of two bromines at C1 and C4 carbons , C1 is primary carbon which is less sterically hindered while C-4 is tertiary carbon and sterically hindered . So it is easy for incoming Nu⁻ to attack on C1 carbon .So Br⁻ is repleaced by I⁻.

1,4-dibromo-4-methylpentane + NaI → 4-bromo-1-iodo-4-methylpentane

The product formed from reaction between 1,4-dibromo-4-methylpentane and NaI is 4-bromo-1-iodo-4-methylpentane . (Image)

B) Reaction with AgNO3 :

Reaction of alkyl halide with AgNO3 in ethanol takes place via SN¹ ( unimolecular nucleophilic substitution ) mechanism . In this leaving group(halide) leaves from alkyl halide forming an intermediate carbocation species . The incoming Nu⁻ attack on this carbocation.

AgNO3 reacts releases Ag⁺ion which abstract Br⁻ of C-4 carbon from 1,4-dibromo-4-methylpentane. THis forms tertiary carbocation which is more stable than carbocation formed by removal of Br from C-1 . The ethanol being more Nucleophilic than NO₃⁻ (from AgNO₃), attacks on this carbocation .(Image )

The product formed as a result is 5-bromo-2-ethoxy-2-methyl pentane.

7 0

3 years ago

How would a flood be a limitation for synthetic polymers that rely on natural rubber in its production?

Zepler [3.9K]

A flood, if it hits the environment of the natural rubbers, would destroy how the rubber is being produced. to have a large amount of limitation, the flood would destroy a large percentage of rubber trees. This natural rubber is needed to make synthetic polymers. Without the rubber (because of damages to it's ecosystem through the flood), there would be a limited supply, and a substancial drop on synthetic polymers.

hope this helps

3 0

3 years ago

Read 2 more answers

Please list about 10 facts about viscosity

MariettaO [177]

Viscosity is the thickness of a liquid, cause by the friction between the molecules in that liquid. A very high viscosity would result in a solid form and low would be a liquid. If a liquid as zero viscosity is only found in superfluids at there freezing points or lower. There are also two types of viscosity “dynamic” (which is measure in seconds, pascal seconds to be exact) and “kinematic” (which is measured in metre per second squared)

Fun fact they use viscosity to predict when volcanoes are going to erupt:)

Hope this helps I love sciencey stuff so if you need anymore help let me know!

5 0

3 years ago

Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo

Romashka-Z-Leto [24]

Answer:

$\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}$

Explanation:

Volume of a cone:

$\displaystyle V=\frac{1}{3} \pi r^2 h$

We have $\displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec}$ and we want to find $\displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ?$ when the height is 2 cm.