4 years ago

What is the hydroxide ion concentration of a solution that has a pH of 8.57?

Chemistry

1 answer:

Inessa [10]4 years ago

4 0

Calculate the pOH first :

pOH =14-8.57=5.43

(OH)=10^-5.47
(OH)=3.72 x 10^-6 mol/L

You might be interested in

Please answer the question

slamgirl [31]

this is a very hard question

8 0

3 years ago

Read 2 more answers

Please help me I really need help

Mars2501 [29]

Answer:

Explanation:

chemically changed

hope it helps!!

8 0

3 years ago

Read 2 more answers

1. Displacement vectors of 10 m west and 14 m west make a resultant vector that is

Iteru [2.4K]

Answer:

B 24 m west I belive that it is the answer

3 0

3 years ago

A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mas

Anna71 [15]

Answer:

$\large \boxed{\text{528.7 g} }$

Explanation:

It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32.00

2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ

n/mol: 7280

1. Moles of O₂

The molar ratio is 25 mol O₂:11 018 kJ

$\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}$

2. Mass of O₂

$\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}$

3 0

3 years ago

Match the part of the wave to the diagram

erik [133]

Answer:

The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5.

Explanation:

The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5 because of the diagram.

5 0

3 years ago