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3 years ago

HELP ASAP!! how can nuclear energy be classified as an inexhaustible energy resource??

Chemistry

1 answer:

seropon [69]3 years ago

6 0

Answer:

No, and yes. As there is a finite amount of matter in the

universe, only so much can be converted to make energy. There will

be a limit, though it is a long, long way from where we are

Explanation:

You might be interested in

What is energy?

Nat2105 [25]

The answer would be the second answer: the property that gives it mass. This is because energy is t<span>he property of an object or system that enables it to do work. </span>

5 0

3 years ago

Read 2 more answers

At what substrate concentration would an enzyme with a K_cat of 30.0 s⁻¹ and a Km of 0.0050 M operate at one-quarter of its maxi

Umnica [9.8K]

Answer:

The correct answer is option B.

Explanation:

Michaelis–Menten 's equation:

$v=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}$

$V_{max}=k_{cat}[E_o]$

v = rate of formation of products

[S] = Concatenation of substrate = ?

$[K_m]$ = Michaelis constant

$V_{max}$ = Maximum rate achieved

$k_{cat}$ = Catalytic rate of the system

$E_o$ = initial concentration of enzyme

We have :

$v=\frac{V_{max}}{4}$

[S] =?

$K_m=0.0050 M$

$v=V_{max}\times \frac{[S]}{(K_m+[S])}$

$\frac{V_{max}}{4}=V_{max}\times \frac{[S]}{(0.0050 M+[S])}$

$[S]=\frac{0.005 M}{3}=1.7\times 10^{-3} M$

So, the correct answer is option B.

8 0

3 years ago

What part of the atom do the different 35 and 37 represent?

loris [4]

It would be atomic masses of the same atoms, and that atoms will be isotopes.

4 0

4 years ago

A 7.27-gram sample of a compound is dissolved in 250 grams of benzene. The freezing point of this solution is 1.02°C below that

almond37 [142]

Answer:

146 g/mol → option b.

Explanation:

This is a problem about the freezing point depression. The formula for this colligative property is:

ΔT = Kf . m . i

We assume i = 1, so our compound is not electrolytic.

ΔT = Freezing T° of pure solvent - Freezing T° of solution = 1.02 °C

m = molality (mol of solute/kg of solvent)

We convert the grams of solvent (benzene) to kg → 250 g . 1 kg/1000 = 0.250 kg.

We replace → 1.02°C = 5.12°C/mol/kg . mol/ 0.250kg . 1

1.02°C / 5.12 mol/kg/°C = mol/ 0.250kg

0.19922 mol/kg = mol/ 0.250kg

mol = 0.19922 . 0.250kg → 0.0498 mol

molar mass = g/mol → 7.27 g / 0.0498mol = 146 g/mol

5 0

3 years ago

Before entering the cyclotron, the particles are accelerated by a potential difference V. Find the speed v with which the partic

vesna_86 [32]

Answer:

Speed, $v=\sqrt{\dfrac{2qV}{m}}$

Explanation:

The device which is used to accelerate charged particles to higher energies is called a cyclotron. It is based on the principle that the particle when placed in a magnetic field will possess a magnetic force. Just because of this Lorentz force it moves in a circular path.

Let m, q and V are the mass, charge and potential difference at which the particle is accelerated.

The work done by the particles is equal to the kinetic energy stored in it such that,

$qV=\dfrac{1}{2}mv^2$

v is the speed with which the particles enter the cyclotron

So,

$v=\sqrt{\dfrac{2qV}{m}}$

So, the speed with which the particles enter the cyclotron is $v=\sqrt{\dfrac{2qV}{m}}$ . Hence, this is the required solution.

7 0

3 years ago