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2 years ago

Hey! Could someone help? spam answers not tolerated

Chemistry

2 answers:

adoni [48]2 years ago

8 0

Answer:

The correct answers are sunlight is bent at a smaller angle and the electrical conductivity of seawater decreases.

Explanation:

Maslowich2 years ago

5 0

1 and 4 are the correct answer

Hope it helps :)

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why do you need to think about polarity of the different ingredients in your salad dressing in order for it to turn out well?

vazorg [7]

So that they combine smoothly and you aren't left with separated looking salad dressing. With polarity only, like-polarities dissolve like-polarities. So you must make sure that all your ingredients are polar or all are nonpolar.

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3 years ago

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A substance stores ___________ as a result of its chemical bonds.

Maksim231197 [3]

Answer:

Chemical energy

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3 years ago

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Sergeeva-Olga [200]

Ok cool, pls help me out check my profile and answer

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3 years ago

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For the reaction A + B + C → D + E, the initial reaction rate was measured for various initial concentrations of reactants. The

babymother [125]

Answer : The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+B+C\rightarrow D+E$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$6.0\times 10^{-4}=k(0.20)^a(0.20)^b(0.20)^c$ ....(1)

Expression for rate law for second observation:

$1.8\times 10^{-3}=k(0.20)^a(0.20)^b(0.60)^c$ ....(2)

Expression for rate law for third observation:

$2.4\times 10^{-3}=k(0.40)^a(0.20)^b(0.20)^c$ ....(3)

Expression for rate law for fourth observation:

$2.4\times 10^{-3}=k(0.40)^a(0.40)^b(0.20)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{1.8\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.20)^a(0.20)^b(0.60)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{2.4\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.40)^a(0.20)^b(0.20)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{2.4\times 10^{-3}}{2.4\times 10^{-3}}=\frac{k(0.40)^a(0.40)^b(0.20)^c}{k(0.40)^a(0.20)^b(0.20)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Thus,

The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

5 0

2 years ago

For the following reaction, 0.511 moles of sulfuric acid are mixed with 0.464 moles of zinc hydroxide. What is the formula for t

kkurt [141]

Answer:

Zinc hydroxide, Zn(OH)₂ is the limiting reactant.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₂SO₄ + Zn(OH)₂ —> ZnSO₄ + 2H₂O

From the balanced equation above,

1 mole of H₂SO₄ reacted with 1 mole of Zn(OH)₂.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of H₂SO₄ reacted with 1 mole of Zn(OH)₂.

Therefore, 0.511 mole of H₂SO₄ will also react with 0.511 mole of Zn(OH)₂.

From the calculation made above, we can see that it will take a higher amount (i.e 0.511 mole) of Zn(OH)₂ than what was given (i.e 0.464 mole) to react completely with 0.511 mole of H₂SO₄.

Therefore, Zn(OH)₂ is the limiting reactant and H₂SO₄ is the excess reactant.

3 0

3 years ago

Hey! Could someone help? *spam answers not tolerated*

Hey! Could someone help? spam answers not tolerated