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Korvikt [17]
3 years ago
13

Hey! Could someone help? *spam answers not tolerated*

Chemistry
2 answers:
adoni [48]3 years ago
8 0

Answer:

The correct answers are sunlight is bent at a smaller angle and the electrical conductivity of seawater decreases.

Explanation:

Maslowich3 years ago
5 0
1 and 4 are the correct answer

Hope it helps :)
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What is the empirical formula for P4O10?
Sphinxa [80]

Answer: P2O5

Explanation: You divide both subscripts by 2 to get the empirical formula.

8 0
3 years ago
Read 2 more answers
The proportion of dissolved substances in seawater is usually expressed in
LiRa [457]

Answer:

The proportion of dissolved substances in seawater is usually expressed in ppm, ppb or ppt

Explanation:

The concentration of very diluted solutions should be expressed in parts per million, billion or trillion.

ppm = mass from the solute . 10⁶ / mass or volume of the solution

ppb = mass from the solute . 10⁹ / mass or volume of the solution

ppt = mass from the solute . 10¹² / mass or volume of the solution

ppm = mg/kg, μg/g, μg/mL → These are the units

ppb = ng/g

ppt = pg/g

3 0
3 years ago
The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri
Nimfa-mama [501]

Answer: The expression for equilibrium constant is \frac{[NH_3]^2}{[H_2]^3[N_2]}

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as k_c

For a general reaction:

aA+bB\rightleftharpoons cC+dD

The equilibrium constant is written as:

k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

Chemical reaction for the formation of ammonia is:

N_2+3H_3\rightleftharpoons 2NH_3

k_c=1.6\times 10^2

Expression for k_c is:

k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}

1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}

8 0
3 years ago
Which is NOT a correct assumption related to the Kinetic Theory?
cestrela7 [59]

Answer:

D

Explanation:

i took the test and got it right :)

7 0
2 years ago
Olive oil has a density of 0.92 g/mL. How much would 1 liter of olive oil weigh in grams?
svp [43]
Dimension analysis is to be used to solve this problem. First convert 1L to milliliters. That is equivalent to 1000 ml. Then by dimension analysis, multiply the volume ( 1000ml) to the density of oil (0.92 g/ml) resulting to the answer: 920 grams. 
4 0
3 years ago
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