Answer:
22.4 L at standard temperature and pressure.
Answer:
92.72 kJ
Explanation:
2 N₂ (g) + O₂ (g) —-> 2 N₂O
According to question , one mole of N₂O requires 163.2 kJ of heat
Molecular weight of N₂O = 44 gm
25 g N₂O = 25 / 44 mole
25 / 44 mole will require 163.2 x 25 / 44 kJ
= 92.72 kJ
1 kg/L -------------- 0.001 kg/mL
22.4 kg/L --------- ??
22.4 x 0.001 / 1 => 0.0224 kg/mL
<span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles
Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq)
Ksp = (Sr++)^3(As04^-3)^2
(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4
(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4
<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th
I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span></span>
