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Mice21 [21]
2 years ago
6

The balls in a modeling kit representing different elements are often distinguished by color. however, there are other ways to i

dentify the elements. beyond color, what differences do you expect between the atoms of distinct elements in a modeling kit?
select one or more:
a. the arrangement of holes in the atoms
b. the material that makes up the atoms
c. the comparative size of the atoms
d. the number of holes in the atoms
Chemistry
1 answer:
nika2105 [10]2 years ago
5 0

The size of the atoms a and the number of holes in the atoms can be used to decode the element.

<h3>What are models?</h3>

A model is a miniature depiction of reality. Molecular models often consists of boxes that contain balls which are used to represent elements. In common parlance, the color is used to show the type of element.

Apart from the color, the size of the atoms a and the number of holes in the atoms can be used to decode the element.

Learn more about molecular models:brainly.com/question/156574

#SPJ1

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200.00 grams of an organic compound is known to contain 83.884 grams of carbon, 10.486
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The empirical formula of a given compound is C6H9ON5.

<u>Explanation</u>:

Step 1: Obtain the mass of each element present in grams

                  Element % = mass in g = m

Carbon = 83.884 grams, Hydrogen = 10.486 grams, Oxygen = 18.640 grams, Nitrogen = 86.99 grams.

Step 2: Determine the number of moles of each type of atom present

                m/atomic mass = Molar amount (M)

Molar amount of carbon = (83.884 1 mol ) / 12 g = 6.99

Molar amount of hydrogen = (10.486  1 mol) / 1 g = 10.49

Molar amount of oxygen = (18.64  1 mol) / 16 g = 1.17

Molar amount of nitrogen = (86.99  1 mol) / 14 g = 6.21

Step 3: Divide the number of moles of each element by the smallest number of moles

            M / least M value = Atomic Ratio (R)

Atomic radius of carbon = 6.99 / 1.17 = 5.9 = 6

Atomic radius of hydrogen = 10.49 / 1.17 = 8.9 = 9

Atomic radius of oxygen = 1.17 / 1.17 = 1

Atomic radius of nitrogen = 6.21 / 1.17 = 5

Step 4: Convert numbers to whole numbers. This set of whole numbers are the subscripts in the empirical formula.

            R * whole number = Empirical Formula

The empirical formula of a given compound is C6H9ON5.

7 0
4 years ago
The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa
Ostrovityanka [42]

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

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3 years ago
All of the following are solutions except?
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