2 years ago

Please help you kind people

Mathematics

1 answer:

mafiozo [28]2 years ago

5 0

Answer:

All I know is that the first picture is 8

Step-by-step explanation:

I know because one times eight is eight so um yeah

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A square pyramid has sides of 4.1 cm, and a pyramid height of .6 cm, determine the volume.

Rainbow [258]

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3 years ago

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valentinak56 [21]

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3 years ago

Solve. x² – 5x + 6 = 0 {–2, –3} {2, 3} {3, –2} {5, –1}

ddd [48]

What 2 numbes multiply go get 6 and add to get -5
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3 years ago

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

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3 years ago

Can someone find the answer

Alexus [3.1K]

Answer:

it is B.

Step-by-step explanation:

B. can i have brainlyest please

7 0

2 years ago

Read 2 more answers