It is the thermal energy transferred from a hot object to a cool object.
The following statement listed above is correct.
Answer: True.
We can use constant acceleration equation to solve for the distance.
Formula is:
Vf^2 = Vi^2 + 2ad
where Vf^2 is final velocity squared, Vi^2 is initial velocity squared, a is acceleration (or deceleration) and d is the distance.
we want the car to come to complete stop, that is, Vf^2 be equal to zero.
Therefore, the equation becomes 0 = Vi^2 + 2ad. Solving for d we get:
d = (-(Vi)^2)/2a). We can ignore the minus sign since acceleration is really deceleration.
We know initial velocity (23m/s) and we know acceleration (max= 300 m/s^2). Plugging these in, we get:
d = ((23 m/s)^2)/(2* 300m/s^2) = <span>0.88m </span>
<span>hope that helps</span>
Answer:
<em>10.09 units</em>
Explanation:
For the A
Ax = -8.0 units
Ay = 6.0 units
The resultant vector = Ra = 
Ra = 
= 10 units
For B
Bx = 1.0 units
By = -1.0 units
The resultant vector = Rb = 
Rb = 
= 
units
Adding these two vectors A and B together, magnitude of vector R is
R = 
R = 
= <em>10.09 units</em>
Angular momentum is the measure of the amount of rotation of the body. It is the product of the moment of inertia and the angular velocity. The moment of inertia has the equation I=mr^2, where m is the mass and r is the radius of the circle. In this case, the radius is 0.6 m. Then, I = 2kg * (0.6)^2 = 0.72 kg-m2/s2.
The angular velocity on the other hand is the product of linear velocity and the radius. The equation is ω = rv, where v is the linear velocity. Therefore, ω = 0.6*1.1 = 0.66 rad/s
Therefore, the angular momentum is
= 0.72 kg-m2/s2*0.66 rad/s
= 0.48 kg-m^2/s
