Answer:
You can't do exercise or play tag. You can't do sports. You can't reach high places.
Answer: 39.2m/s
Explanation:
Due to the free falling body, the acceleration of the ball is 9.8 m/s^2, and its initial velocity is 0 m/s.
V(t) = g*t
The change of velocity from t=1 to t=5:
Delta V = 9.8*(5-1) = 39.2 m/s
The answer is A I believe. Hope this helps!
Answer:
4,444,471 m/s
Explanation:
Use the momentum-impulse equation to find the change in velocity:
I = Δp = mΔv
We know the impulse given as well as the mass, we are trying to find the change in velocity hence the question how fast the car is going afterwards.
8.0*10^9 = 1800Δv
Simply divide 1800 to isolate Δv which gives:
4.4*10^6 = Δv
According to the calculator, the 4 is repetitive across all values so therefore it gives:
4,444,444 m/s = Δv
Now find the final/afterwards velocity:
vi + Δv = vf
27 + 4,444,444 = vf
4,444,471 = vf
The impulse given by the engine is out of this world quite literally.
Answer:
Explanation:
Given that,
Ship send 1200Hz down in to the water.
Echo is heard after 3secs
f = 1200Hz
t = 3seconds
Using wave equation
V = fλ
In echo, two distance is travelled before echo can be heard, then we have
V = 2λ × f
Making d subject of the formula
λ = V / ( 2 × f)
So,
As frequency is reduced by half, the wavelength is double.
Notice
That the sound will travel the same distance but only the speed and the frequency will change.
So, the sound would travel twice as fast, so it would take half as much time to return