Earth has a magnetic dipole moment of 8.0 × 1022 J/T. (a) What current would have to be produced in a single turn of wire extend
ing around Earth at its geomagnetic equator if we wished to set up such a dipole? Could such an arrangement be used to cancel out Earth's magnetism (b) at points in space well above Earth's surface or (c) on Earth's surface? Round your answer (a) to 3 significant digits.
1 answer:
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Answer:
7.9
Explanation:
When we put the metal piece in the liquid (which is in the graduated cylinder), how much it goes up is equal to the volume of the piece we inserted.
So now we know that the volume of that piece of unknown metal is 7mL (which is the same as 7).
Density is .
So the density of that piece of metal is
Which leaves us with a final density of 7.9
348.34 m/s. When Superman reaches the train, his final velocity will be 348.34 m/s.
To solve this problem, we are going to use the kinematics equations for constant aceleration. The key for this problem are the equations and
where
is distance,
is the initial velocity,
is the final velocity,
is time, and
is aceleration.
Superman's initial velocity is , and he will have to cover a distance d = 850m in a time t = 4.22s. Since we know
,
and
, we have to find the aceleration
in order to find
.
From the equation we have to clear
, getting the equation as follows:
.
Substituting the values:
To find we use the equation
.
Substituting the values:
Answer:
The voltage drop across the bulb is 115 V
Explanation:
The voltage drop equation is given by:
Where:
ΔW is the total work done (4.6kJ)
Δq is the total charge
We need to use the definition of electric current to find Δq
Where:
I is the current (2 A)
Δt is the time (20 s)
Then, we can put this value of charge in the voltage equation.
Therefore, the voltage drop across the bulb is 115 V.
I hope it helps you!