Answer:
Time taken by the arrow to travel along to hit the ground is 0.55 seconds.
Explanation:
The only "force" acting on the "crossbow" to cause it to "hit" the ground is "gravity". There is no initial velocity downward when it shoot.
d = the displacement of the object
t = the time for which the object moved
a = acceleration of the object
= the initial velocity of the object
Given values
d = 1.5 m
t = unknown
Square root both sides
t = 0.55 s
-90.0 °F = -67 and 7/9 °C
-90.0 °F also = +205.372 K
-5.0 °C = +23 °F
-5.0 °C also = +268.15 K
It is an example of Hypermobility.
To solve this process it is necessary to consider the concepts related to the relations between pressure and temperature in an adiabatic process.
By definition the relationship between pressure and temperature is given by
Here
P = Pressure
T = Temperature
The ratio of specific heats. For air normally is 1.4.
Our values are given as,
Therefore replacing we have,
Solving for 
Therefore the maximum theoretical pressure at the exit is 
Momentum should be conserved. The momentum of both
objects must balance with their initial and final momentum.
Let m1 and v1 be the mass and velocity of the
bowling ball
And m2 and v2 be the mass and velocity of the
bowling pin
(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f
30 kg m/s + (1.5 kg)(0 m/s) = 13kg m/s + 1.5v2f
V2f = 11.33 m/s
<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>
