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What did johannes kepler contribute to the study of planets

Nana76 [90]

Johannes Kepler was a main stargazer of the Scientific Revolution known for detailing the Laws of Planetary Motion. A stargazer, obviously, is a man who contemplates the sun, stars, planets and different parts of room. Kepler was German and lived in the vicinity of 1571 and 1630.
Despite the fact that Kepler is best known for characterizing laws in regards to planetary movement, he made a few other striking commitments to science. He was the first to discover that refraction drives vision in the eye and that utilizing two eyes empowers profundity recognition.

4 0

2 years ago

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A 4.9-MeV (kinetic energy) proton enters a 0.28-T field, in a plane perpendicular to the field. Part APart complete What is the

BartSMP [9]

Answer:

$r=1.14m$

Explanation:

$\theta$ is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

$F_m=qvBsen\theta\\F_m=qvBsen(90^\circ)\\F_m=qvB$

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

$F_m=F_c\\qvB=F_c(1)$

$F_c$ is the centripetal force and is defined as:

$F_c=m\frac{v^2}{r}$

Here $v$ is the proton's speed and $r$ is the radius of the circular motion. Replacing this in (1) and solving for r:

$qvB=\frac{mv^2}{r}\\r=\frac{mv^2}{qvB}\\r=\frac{mv}{qB}$

Recall that 1 J is equal to $6.242*10^{12}MeV$ , so:

$4.9MeV*\frac{1J}{6.242*10^{12}MeV}=7.85*10^{-13}J$

We can calculate $v$ from the kinetic energy of the proton:

$K=\frac{mv^2}{2}\\\\v=\sqrt{\frac{2K}{m}}\\v=\sqrt{\frac{2(7.85*10^{-13}J)}{1.67*10^{-27}kg}}\\v=3.06*10^{7}\frac{m}{s}$

Finally, we calculate the radius of the proton path:

$r=\frac{mv}{qB}\\r=\frac{1.67*10^{-27}kg(3.06*10^{7}\frac{m}{s})}{1.6*10^{-19}C(0.28T)}\\r=1.14m$

8 0

3 years ago

A thermally isolated system is made up of a hot piece of aluminum and a cold piece of copper; the aluminum and the copper are in

butalik [34]

Answer:

copper will have more change in temperature as compare with aluminum

Explanation:

Hot piece of copper is made in contact with cold piece of aluminium

So here thermal energy transfer will take place from copper to aluminium

so by energy conservation we can say that heat given by copper is same as the heat absorbed by aluminium.

now we have

$m_1s_1\Delta T_1 = m_2s_2\Delta T_2$

here we know that

$s_1$ = specific heat capacity of copper

$s_2$ = specific heat capacity of aluminum

given that specific heat capacity of aluminium is more than double that of copper

so we can say

$s_2 = 2s_1$

so here if the mass of copper and aluminium is same then

$\Delta T_1 = 2 \Delta T_2$

so temperature change of copper is twice the temperature change of aluminium

So copper will have more change in temperature as compare with aluminum

4 0

3 years ago

How many atoms are in SO<br> 3

kkurt [141]

Answer:

There are 6.87 x 1023 atoms in 1.14 mol SO3, or sulfur trioxide :

3 0

3 years ago

For the simple harmonic motion equation

My name is Ann [436]

Given that : d = 5sin(pi t/4), So, maximum displacement, d = 5*(+1) = 5 Also, maximum displacement, d = 5*(-1) = -5

3 0

3 years ago