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Reil [10]
3 years ago
5

Which is an example of a superconductor?

Physics
1 answer:
astra-53 [7]3 years ago
3 0
Diamond,Aluminium,<span>Gallium</span>
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A spring has a spring constant of 53N/m. How much elastic potential energy is stored in the spring in the spring when it is comp
IRISSAK [1]

Answer:11686.5 joules

Explanation:

elastic constant(k)=53N/m

extension(e)=21m

Elastic potential energy=(k x e^2)/2

Elastic potential energy=(53 x (21)^2)/2

Elastic potential energy=(53x21x21)/2

Elastic potential energy=23373/2

Elastic potential energy=11686.5

Elastic potential energy is 11686.5 joules

5 0
3 years ago
An air conditioner running with R-134a on a cycle executed under the saturationdome between the pressure limits of 0.8 MPa and 0
ohaa [14]

Answer:

The COP of the system is = 4.6

Explanation:

Given data

Higher pressure  = 1.8 M pa

Lower pressure = 0.12 M pa

Now we have to find out high & ow temperatures at these pressure limits.

Higher temperature corresponding to pressure 1.8 M pa

T_{H} = 62.9 °c = 335.9 K

Lower temperature corresponding to pressure 0.2 M pa

T_{L} = - 10.1 °c = 262.9 K

COP of the system is given by

COP = \frac{T_{L} }{T_{H} -T_{L}   }

COP = \frac{335.9}{335.9 -262.9}

COP = 4.6

Therefore the COP of the system is = 4.6

8 0
3 years ago
A vehicle reaches a speed of 7.5 m/s over 15 seconds. What is its acceleration if it
denpristay [2]

acceleration = \frac{velocity}{time}  = \frac{7.5}{15}  = 0.5ms^-^2

So the answer is option b.

8 0
3 years ago
which of the following is the correct si unit to use in measuring the mass of a boulder a. tons b. kilograms c. ounces d. pounds
Salsk061 [2.6K]
B. kilograms iuyiuiuhikj
7 0
3 years ago
Read 2 more answers
A penny is dropped off the top of the Stratosphere from rest and falls freely with the
Roman55 [17]

Answer:

S = 122.5m

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 5 seconds

Since it's a free fall, initial velocity, u = 0

To find the displacement, we would use the second equation of motion given by the formula;

S = ut + \frac {1}{2}at^{2}

Where;

  • S represents the displacement or height measured in meters.
  • u represents the initial velocity measured in meters per seconds.
  • t represents the time measured in seconds.
  • a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

S = 0*5 + \frac {1}{2}*(9.8)*5^{2}

S = 0 + 4.9*25

S = 122.5m.

3 0
3 years ago
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