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11Alexandr11 [23.1K]
3 years ago
9

The direction in which a chemical reaction occurs is represented by an ___

Physics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

In a reversible reaction, both forward and reverse directions of the reaction generally occur at the same time. While reactants are reacting to produce products, products are reacting to produce reactants. Often, a point is reached at which forward and reverse directions of the reaction occur at the same rate.

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A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
SOVA2 [1]

Answer:

The density of the mixture is 0.55kg/m^3

Explanation:

P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole

PV = nRT

V = nRT/P = 1×8.314×273/100 = 22.70m^3

Mass of N2 = 0.4×28 = 11.2kg

Mass of H2 = 0.6×2 = 1.2kg

Mass of mixture = 11.2 + 1.2 = 12.4kg

Density of mixture = mass/volume = 12.4/22.7 = 0.55kg/m^3

3 0
3 years ago
you spray your sister with water from a garden hose. the water is supplied to the hose at a rate of 0.649x10-3 m^3/s and the dia
Ivanshal [37]

Answer:

27.82 m/s

Explanation:

The radius of the hose is half of its diameter

r = d/2 = 5.45\times10^{-3}/2 = 0.002725 m

So its area must be

A = \pi r^2 = \pi 0.002725^2 = 2.33\times10^{-5} m^2

The speed of water coming out of the hose is its flow rate divided by the cross-section area of the hose

v = \dot{V}/A =0.000649 / 2.33\times10^{-5} = 27.82 m/s

7 0
3 years ago
How is light energy converted to chemical energy in photosynthesis?
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7 0
3 years ago
Why does a car slide when it rolls over an icy patch on a road?
Rainbow [258]
Hello. The answer, though I don't know what options you need to be answered, is that there is less friction between the car tires and the ice, than when they are on the road. Causing the car to slide.
7 0
3 years ago
You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a
expeople1 [14]

Answer:

L=55.9m

Explanation:

The equation for the period of a simple pendulum is:

T=2\pi\sqrt{\frac{L}{g}}

In our case what we know is the period and the acceleration of gravity, and we need to know the length of the pendulum, so we can write:

L=(\frac{T}{2\pi})^2g

Which for our values is:

L=(\frac{15s}{2\pi})^2(9.81m/s^2)=55.9m

7 0
3 years ago
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