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Ksju [112]
3 years ago
15

Which organ allows the exchange of oxygen and carbon dioxide?​

Physics
2 answers:
kotegsom [21]3 years ago
7 0
A specific organ would be the lungs.
jok3333 [9.3K]3 years ago
3 0

Answer:

Respiratory System

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Two formats of sources are
Scilla [17]

Answer:

APA and MLA are the two format sources.

Don't forget to keep me in top brainlist

3 0
2 years ago
We all have a tendency to make illusory correlations from time to time. Try to think of an illusory correlation that is held by
Artist 52 [7]

Answer:

Thats a personal question

Explanation:

It asks about you

(illusion is something you think is there but is not)

5 0
2 years ago
A dentist uses a concave mirror (focal length 2.5 cm) to examine some teeth. If the distance from the object to the mirror is 1.
AysviL [449]

Answer:

2.28

Explanation:

From mirror formula,

1/f = 1/u+1/v .......... Equation 1

Where f = focal length of the mirror, v = image distance, u = object distance.

Note: The focal length mirror is positive.

make v the subject of the equation,

v = fu/(u-f)............ Equation 2

Given: f = 2.5 cm, u = 1.4 cm

Substitute into equation 2

v = 2.5(1.4)/(1.4-2.5)

v = 3.5/-1.1

v = -3.2 cm.

Note: v is negative because it is a virtual image.

But,

Magnification = image distance/object distance

M = v/u

Where M = magnification.

Given: v = 3.2 cm, u = 1.4 cm

M = 3.2/1.4

M = 2.28.

Thus the magnification of the tooth = 2.28.

3 0
3 years ago
I dolt understand what to do next please help
lidiya [134]
Divide 24 by 12.
24/t = 12
24/12 = t
24/12 = 2
t = 2
6 0
3 years ago
Helpp me pleassee....
lilavasa [31]

Answer:

The fundamental wavelength of the vibrating string is 1.7 m.

Explanation:

We have,

Velocity of wave on a guitar string is 344 m/s

Length of the guitar string is 85 cm or 0.85 m

It is required to find the fundamental wavelength of the vibrating string. The fundamental frequency on the string is given by :

f=\dfrac{v}{2l}\\\\f=\dfrac{344}{2\times 0.85}\\\\f=202.35\ Hz

Now fundamental wavelength is :

\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{344}{202.35}\\\\\lambda=1.7\ m

So, the fundamental wavelength of the vibrating string is 1.7 m.

4 0
3 years ago
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