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2 years ago

18. Reference samples come from a source that is O known O scientific method O physical evidence O individual characteristics

Physics

1 answer:

zheka24 [161]2 years ago

4 0

Answer:

O scientific method

Explanation:

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Describe how light is used in modern forms of communication.

Kobotan [32]

Answer:Visible light communication (VLC) is a wireless method that uses light emitted by LEDs to deliver networked, mobile, high-speed communication similar to Wi-Fi, leading to the term Li-Fi. It can be used as standalone solution or in a supplementary role to radio-frequency (RF) or cellular network communication

Explanation:

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2 years ago

When matter changes from one state to another, what do we call this process? A. a physical change B. a nuclear change C. an expl

klemol [59]

A. physical change

Look at the way water freezes and changes to ice. The matter is still going to be the same. its just the physical property that changed.

PHYSICAL= TEMPORARY
CHEMICAL= PERMANENT

3 0

2 years ago

Read 2 more answers

2 equal charges, 27 micro Coulomb each, are separated by 5 cm. Find force between those.

padilas [110]

Answer:

The force between charges is $F= 2.624*10^3N$ .

Explanation:

The Coulomb force $F$ between the two charges $q_1$ and $q_2$ separated by distance $d$ is given by the equation

$F = k\dfrac{q_1q_2}{d^2}$

where $k$ is the coulombs constant, and has the value

$k= 9*10^9N\cdot C\cdot m^2$ .

Now in our case

$q_1=q_2=27\mu C =27*10^{-6}C$

and

$d= 5cm =0.05m$ ,

therefore, the Coulomb force between the charges is

$F =( 9*10^9N\cdot C\cdot m^2)*\dfrac{(27*10^{-6}C)(27*10^{-6}C)}{(0.05m)^2}$

$\boxed{ F= 2.624*10^3N}$

3 0

2 years ago

The rate at which speed changes is called

sergiy2304 [10]

Answer:

meters per second

Explanation:

7 0

2 years ago

Read 2 more answers

Imagina que compras una placa rectangular de metal de 2mm de alto, 10mm de ancho x 50mm de largo, y una masa de 0.02kg. El vende

shusha [124]

Answer:

Densidad de la placa = 20 g/cm³.

La placa no es de oro.

Explanation:

Para encontrar la densidad de la placa rectangular primero debemos hallar su volumen:

$V = 2 mm*10 mm*50 mm = 1000 mm^{3}*\frac{1 cm^{3}}{(10 mm)^{3}} = 1 cm^{3}$

Ahora, encontremos al densidad de la placa:

$d = \frac{m}{V} = \frac{20 g}{1 cm^{3}} = 20 g/cm^{3}$

Dado que la densidad del oro es 19.32 g/cm³ y que la densidad de la placa rectangular calculada es 20 g/cm³, podemos decir que dicha placa no es de oro.

Espero que te sea de utilidad!

6 0

2 years ago

18. Reference samples come from a source that is O known O scientific method O physical evidence O individual characteristics​

18. Reference samples come from a source that is O known O scientific method O physical evidence O individual characteristics