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Alisiya [41]
3 years ago
8

10. What effect does temperature have on molecular motion? Using this explanation, explain why both pressure and volume can decr

ease with decreasing temperature.
Chemistry
1 answer:
vovangra [49]3 years ago
5 0

Answer:

If the temperature increases the molecular movement as well, and if it increases the same it will happen with the molecular movement.

Pressure, volume and temperature are three factors that are closely related since they increase the temperature, the pressure usually decreases due to the dispersion of the molecules that can be generated, so the volume also increases.

If the temperature drops, the material becomes denser, its molecules do not collide with each other, their volume and pressure increases.

Explanation:

The pressure is related to the molecular density and the movement that these molecules have.

The movement is regulated by temperature, since if it increases, the friction and collision of the molecules also.

On the other hand, the higher the volume, the less pressure there will be on the molecules, since they are more dispersed among themselves.

(in the opposite case that the volume decreases, the pressure increases)

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A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?
Katen [24]

Answer:

T2 = 260 K  

Explanation:

<em>Given data:</em>

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K  

V1 = 1.75 L  

P2 = 210.0 kPa  

V2 = 1.30 L

<em>To find:</em>

T2 = ?

<em>Formula:</em>

\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}

<em>Calculation:</em>

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K  

8 0
3 years ago
Consider three gases: Ar, SF6, and Cl2. If 50.0 grams of these gases are placed in each of three identical containers, which con
adoni [48]
The ideal gas law:
pV=nRT \Rightarrow p=\frac{nRT}{V}
p - pressure, n - number of moles, R - the gas constant, T - temperature, V - volume

The volume and temperature of all three containers are the same, so the pressure depends on the number of moles. The greater the number of moles, the higher the pressure.
The mass of gases is 50 g.

Ar \\&#10;M \approx 39.948 \ \frac{g}{mol} \\&#10;n=\frac{50 \ g}{39.948 \ \frac{g}{mol}} \approx  1.25 \ mol \\ \\&#10;SF_6 \\&#10;M \approx 146.06 \ \frac{g}{mol} \\&#10;n=\frac{50 \ g}{146.06 \ \frac{g}{mol}} \approx 0.34 \ mol \\ \\&#10;Cl_2 \\&#10;M=70.9 \ \frac{g}{mol} \\&#10;n=\frac{50 \ g}{70.9 \ \frac{g}{mol}} \approx 0.71 \ mol

The greatest number of moles is in the container with Ar, so there is the highest pressure.
4 0
3 years ago
What is the process of breaking down food to release energy by adding oxygen
a_sh-v [17]
I believe this process is called cellular respiration. 
6 0
3 years ago
How many molecules are in 100 grams of HCL?
MatroZZZ [7]
There are 2.74266105043 molecules in 100 grams of HCL.
6 0
2 years ago
Read 2 more answers
How much energy is required to vaporize 48.7 g of dichloromethane (CH2Cl2) at its boiling point, if its ΔHvap is 31.6 kJ/mol?
BartSMP [9]

Answer:

The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point

Explanation:

To solve the above question we have the given variable as follows

ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole

However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.

The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles

Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ

3 0
3 years ago
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