The complete balanced chemical reactions are:
<span>HNO3 => CaCO3
+ 2HNO3 → Ca(NO3)2 + H2O + CO2(g)</span>
<span>H2SO4 => CaCO3
+ H2SO4 → CaSO4 + H2O + CO2(g) </span>
<span>So we see that 1 mole of CaCO3 is needed for 2 moles of HNO3 and similarly
to 1 mole of H2SO4.
</span>The number of moles can be calculated as the product of
volume and molarity, so:
moles H2SO4 = 1.7×10^−5 M * (15.5 x 10^9 L) = 263,500 mol
H2SO4
moles HNO3 = 8.9×10^−6 M * (15.5 x 10^9 L) = 137,950 mol
HNO3
So the total moles of CaCO3 required is:
moles CaCO3 = 263,500 mol * 1 + 137,950 mol * (1/2)
moles CaCO3 = 332,475 mol
The molar mass of CaCO3 is 100.086 g/mol, so the mass is:
mass CaCO3 = 332,475 mol * 100.086 g/mol
mass CaCO3 = 33,276,092.85 g = 33.3 x 10^3 kg
Answer:
There will be 525.2 grams of K3N produced
Explanation:
Step 1: Data given
Number of moles of potassium oxide ( K2O) = 6 moles
Magnesium nitride (Mg3N) = in excess
Molar mass of K3N = 131.3 g/mol
Step 2: The balanced equation
Mg3N2 + 3K2O → 3MgO + 2K3N
Step 3: Calculate moles of K3N
The limiting reactant is K2O.
For 1 mol Mg3N2 consumed, we need 3 moles of K2O to produce 3 moles of MgO and 2 moles of K3N
For 6 moles K2O we'll have 2/3 * 6 = 4 moles of K3N
Step 4: Calculate mass of K3N
Mass of K3N = moles K3N * molar mass K3N
Mass of K3N = 4 moles * 131.3 g/mol
Mass of K3N = 525.2 grams
There will be 525.2 grams of K3N produced
A Daisy is eukaryote it is classified in the kingdom of Plantae which all plants are eukaryotic<span />
Which alcahol will behave most like water?
<span> C2H5OH
</span>hope it helps