Question

1- A sample of gas is in a 3.00 L contain at a pressure of 740.0 mmHg. What is the new pressure of the sample if the container's volume is reduced to 1.25 L? Show work.​

Answer 1

Considering the Boyle's law, the new pressure of the sample is 1,776 mmHg.

What is Boyle's law

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

Boyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:

P1×V1=P2×V2

New pressure

In this case, you know:

• P1= 740 mmHg
• V1= 3 L
• P2= ?
• V2= 1.25 L

Replacing in Boyle's law:

740 mmHg× 3 L=P2× 1.25 L

Solving:

P2= (740 mmHg× 3 L) ÷ 1.25 L

P2= 1,776 mmHg

Finally, the new pressure of the sample is 1,776 mmHg.

Learn more about Boyle's law:

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Answer 2

The new pressure of the sample is 1776 mm of Hg, if the container's volume is reduced to 1.25 L as according to Boyle's law,

What is Boyle's law ?

It is the relationship between the pressure and the volume of a gas at constant temperature.

According to this law, the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure.

This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Mathematically, Boyle's law is expressed as:

PV = K

Now it is possible to assume that you have a certain volume of gas V₁ which is at a pressure P₁ at the beginning of the experiment.

If you vary the volume of gas to a new value V₂, then the pressure will change to P₂

Now,

P₁ × V₁ = P₂ × V₂

We know ;

P₁= 740 mmHg

V₁= 3 L

P₂= ?

V₂= 1.25 L

Putting all above values in Boyle's law :

740 mmHg × 3 L = P₂ × 1.25 L

P₂= (740 mmHg× 3 L) ÷ 1.25 L

P₂= 1776 mmHg

The new pressure of the sample is 1776 mm of Hg, if the container's volume is reduced to 1.25 L as according to Boyle's law,

Learn more about Boyle's law :

brainly.com/question/4147359

#SPJ1