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TiliK225 [7]
2 years ago
11

1- A sample of gas is in a 3.00 L contain at a pressure of 740.0 mmHg. What is the new pressure of the sample if the container's

volume is reduced to 1.25 L? Show work.​
Chemistry
2 answers:
inna [77]2 years ago
7 0

Considering the Boyle's law, the new pressure of the sample is 1,776 mmHg.

<h3>What is Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

Boyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:

P1×V1=P2×V2

<h3>New pressure</h3>

In this case, you know:

  • P1= 740 mmHg
  • V1= 3 L
  • P2= ?
  • V2= 1.25 L

Replacing in Boyle's law:

740 mmHg× 3 L=P2× 1.25 L

Solving:

P2= (740 mmHg× 3 L) ÷ 1.25 L

P2= 1,776 mmHg

Finally, the new pressure of the sample is 1,776 mmHg.

Learn more about Boyle's law:

brainly.com/question/4147359

#SPJ1

kramer2 years ago
4 0

The new pressure of the sample is 1776 mm of Hg, if the container's volume is reduced to 1.25 L as according to Boyle's law,

<h3>What is Boyle's law ?</h3>

It is the relationship between the pressure and the volume of a gas at constant temperature.

According to this law, the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure.

This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Mathematically, Boyle's law is expressed as:

PV = K

Now it is possible to assume that you have a certain volume of gas V₁ which is at a pressure P₁ at the beginning of the experiment.

If you vary the volume of gas to a new value V₂, then the pressure will change to P₂

Now,

P₁ × V₁ = P₂ × V₂

We know ;

P₁= 740 mmHg

V₁= 3 L

P₂= ?

V₂= 1.25 L

Putting all above values in Boyle's law :

740 mmHg × 3 L = P₂ × 1.25 L

P₂= (740 mmHg× 3 L) ÷ 1.25 L

P₂= 1776 mmHg

The new pressure of the sample is 1776 mm of Hg, if the container's volume is reduced to 1.25 L as according to Boyle's law,

Learn more about Boyle's law :

brainly.com/question/4147359

#SPJ1

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Calculate the change in pH when 71.0 mL of a 0.760 M solution of NaOH is added to 1.00 L of a solution that is 1.0O M in sodium
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Explanation:

It is known that pK_{a} value of acetic acid is 4.74. And, relation between pH and pK_{a} is as follows.

                    pH = pK_{a} + log \frac{[CH_{3}COOH]}{[CH_{3}COONa]}

                          = 4.74 + log \frac{1.00}{1.00}

So, number of moles of NaOH = Volume × Molarity

                                                   = 71.0 ml × 0.760 M

                                                    = 0.05396 mol

Also, moles of  CH_{3}COOH = moles of CH_{3}COONa

                                          = Molarity × Volume

                                          = 1.00 M × 1.00 L

                                          = 1.00 mol

Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

            CH_{3}COONa + NaOH \rightarrow CH_{3}COOH

Initial :    1.00 mol                                  1.00 mol

NaoH addition:               0.05396 mol

Equilibrium : (1 - 0.05396 mol)    0           (1.00 + 0.05396 mol)

                    = 0.94604 mol                       = 1.05396 mol

As, pH = pK_{a} + log \frac{[CH_{3}COONa]}{[CH_{3}COOH]}

               = 4.74 +  log \frac{0.94604}{1.05396}

               = 4.69

Therefore, change in pH will be calculated as follows.

                         pH = 4.74 - 4.69

                               = 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

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<h3>What is density?</h3>

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Density = mass/volume

volume = mass/density

at a constant density, the volume of an object is proportional to its mass.

From the question, you have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g, the new mass will take the following volume.

180 g = 36 cm³

90 g =  ?

= (90 x 36) / 180

= 18 cm³

Thus, if you were to cut the radium  in half and have only 90 g, it will take up 18 cm³.

Learn more about radium here: brainly.com/question/23781489

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