<h3>
Answer:</h3>
5.6 Liters
<h3>
Explanation:</h3>
- N.T.P. refers to the standard temperature and pressure (S.T.P).
We need to know that;
- One mole of a gas occupies a volume of 22.4 liters at N.T.P.
In this case;
We have 11 g of CO₂
But, 1 mole of CO₂ occupies 22.4 l at N.T.P.
1 mole of CO₂ = 44 g
Therefore;
44 g of CO₂ = 22.4 liters
What about 11 g ?
= (11 g × 22.4 l)÷ 44 g
= 5.6 l
Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.
Answer: False, I believe.
Explanation: If a Hypothesis is proven correct, then another experiment to strengthen that Hypothesis is should be done.
The correct answer is A, B and C
Answer:
- Elimination
- Elimination
- Zaitsev
- Zaitsev
- Carbocation
Explanation:
- The mechanism is generally accepted to always operate via an ELIMINATION step-wise process.
- The ELIMINATION mechanism process will always produce (after dehydration) a ZAITSEV style alkene as major product
- The driving force for the production of this ZAITSEV style alkene product is generally going to be determined by stability of the CARBOCATION
Elimination mechanism is the removal of two substituents from a molecule in either a one- or two-step mechanism
Carbocation is a molecule containing a positive charged carbon atom and three bonds
1. The third option is the least soluble in water because it is the chain with the most number of hydrocarbons. Next is the second option while the first one is the most soluble.
2. Statements 1 and 2 are true. The third option is not true all the time because it depends on the structure of the compound.
