Answer:
- <em>Alkali metals react with water to produce </em><u>hydroxide and hydrogen gas</u><u>.</u>
Explanation:
That is a chemical property of <em>alkali metals</em>: they are highly reactive and <em>react </em>vigorously <em>with water</em> to produce the correspondant hydroxide and hydrogen gas.
These are some of those reactions:
- 2Li (s) + 2H₂O (l) → 2LiOH (aq) + H₂(g) ↑
- 2Na (s) + 2H₂O (l) → 2NaOH (aq) + H₂(g) ↑
- 2K (s) + 2H₂O (l) → 2KOH (aq) + H₂(g) ↑
The alkali metals are the elements of group 1 of the periodic table: Li, Na, K, Rb, Cs, and Fr. They have one valence electron which may lose easily to form an ion with charge +1.
Answer:
need points rn sorry bro hope u get ur answer
Explanation:
Answer:
Acid-Catalyzed Ester Hydrolysis
Explanation:
Fischer Esterification is a reversible reaction and the Le Châteliers principle can be used for the reaction to be completed. For the reverse reaction of Fischer Esterification, using the hydrolysis of ethyl ethanoate, the steps involved are:
1) An hydrogen ion is added to the ester and one of the lone pairs on the oxygen double-bonded to the carbon atom takes the hydrogen ion.
2) The lone pairs on the oxygen of a water molecule takes the positive charge on the carbon atom.
3) The hydrogen ion is transferred from one oxygen atom to another.
4) Then an ethanol molecule is released (one of the products).
5) Reaction with a water molecule releases hydrogen from the oxygen and the other product (ethanoic acid) is formed.
Answer:
1.1 g Na2SO4
Explanation:
First convert mL to L. Then multiply by the Molarity to get moles, then multiply by the molar mass to get grams.
15 mL x 1 L x 0.50 mol Na2SO4 x 142 g = 1.1 g
10^3 mL 1 L mol Na2SO4
You need to use the equation q=mcΔT.
q=the heat absorbed or released
m= the mass of the sample (in this case 250g)
c=the specific heat of the sample (in this case 4.18J/g°C)
ΔT=the change in temperature (in this case 5°C)
When you plug every thing in you should get q=5225J or 5.225kJ
I hope this helps. Let me know if anything is unclear.
