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4 years ago

Does Charles’s law hold when the gas becomes a liquid?

Chemistry

1 answer:

AleksandrR [38]4 years ago

7 0

NO, Charles’s law DOES NOT hold when the gas becomes a liquid

Explanation:

No, Charles's law would not apply to solids and liquids.

This is because liquids and solids have different properties and behaviors compared to gases. For example, both liquids and solids are only slightly compressible even under high pressure because of their particles that are very close together. Gases, also, occupy an indefinite volume (unless in a container), unlike solids and liquids.

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calculate the number of grams of CH3COONa * 3H2O (sodium acetate tri-hydrate) needed to make 250.0 mL of a CH3COOH (acetic acid)

anastassius [24]

Answer:

10.88 g

Explanation:

We have:

[CH₃COOH] = 0.10 M

pH = 5.25

Ka = 1.80x10⁻⁵

V = 250.0 mL = 0.250 L

$M_{CH_{3}COONa*3H_{2}O} = molar \thinspace mass = 136 g/mol$

The pH of the buffer solution is:

$pH = pKa + log(\frac{[CH_{3}COONa*3H_{2}O]}{[CH_{3}COOH]})$ (1)

By solving equation (1) for [CH₃COONa*3H₂O] we have:

$log [CH_{3}COONa*3H_{2}O] = pH - pKa + log [CH_{3}COOH]$

$log [CH_{3}COONa*3H_{2}O] = 5.25 - (-log(1.80 \cdot 10^{-5})) + log (0.10) = -0.495$

$[CH_{3}COONa*3H_{2}O] = 10^{-0.495} = 0.32 M$

Hence, the mass of the sodium acetate tri-hydrate is:

$m = moles*M = [CH_{3}COONa*3H_{2}O]*V*M = 0.32 mol/L*0.250 L*136 g/mol = 10.88 g$

Therefore, the number of grams of CH₃COONa*3H₂O needed to make an acetic acid/sodium acetate tri-hydrate buffer solution is 10.88 g.

I hope it helps you!

4 0

3 years ago

How many moles of n are in 0.225 g of n2o?

katrin2010 [14]

<span>First, divide the mass of N2O by it's molar mass of 46 g/mol to determine the number of moles of N2O, then multiply that number by two since there are two moles of N in each mole of the compound N2O. This results in a final answer of 9.78X10^-3 moles of N in 0.225g of N2O.</span>

5 0

3 years ago

Suppose that 0.25 mole of gas C was added to

Juli2301 [7.4K]

Answer:

Pi = 0.25[P(TTL)/n(TTL)]

Explanation:

Let Total Pressure = P(TTL) and Total moles =n(TTL) => n(i)/n(TTL) = P(i)/P(TTL)

Given n(i) = 0.25 => Pi = 0.25[P(TTL)/n(TTL)]

6 0

4 years ago

a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g

leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

Solution :

By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

Therefore , percentage of Na by mass in NaBr will be same for every amount .

Percentage of Na in 9.77 g NaBr is 22.34 % too .

Gram of Na = $9.77\times \dfrac{22.34}{100}=2.18\ g$ .

Hence , this is the required solution .

7 0

3 years ago

The Atlantic Ocean is expanding. What does this tell us about plates under the Atlantic Ocean?

FromTheMoon [43]

B. They are being forced apart.

7 0

3 years ago

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