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rusak2 [61]
3 years ago
5

The specific heat of water is 4.18 J/(g * °C) How much heat, in kilojoules, must be added to 250 g of water to increase the temp

erature of the water by 5.0°C?
Chemistry
1 answer:
katovenus [111]3 years ago
4 0
You need to use the equation q=mcΔT.
q=the heat absorbed or released
m= the mass of the sample (in this case 250g)
c=the specific heat of the sample (in this case 4.18J/g°C)
ΔT=the change in temperature (in this case 5°C)
When you plug every thing in you should get q=5225J or 5.225kJ

I hope this helps.  Let me know if anything is unclear.
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Read 2 more answers
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
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It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

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